Veritas Prep
Emily keeps 12 different pairs of shoes (24 individual shoes in total) under her bed. If her dog drags out two shoes at random, what is the probability that he drags out a matching pair of shoes?
A. 1/144
B. 1/66
C. 1/23
D. 1/12
E. 1/11
OA C
Emily keeps 12 different pairs of shoes (24 individual shoes
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P(dog selects matching pair) = P(dog chooses ANY sock 1st AND 2nd sock matches the 1st sock)AAPL wrote:Veritas Prep
Emily keeps 12 different pairs of shoes (24 individual shoes in total) under her bed. If her dog drags out two shoes at random, what is the probability that he drags out a matching pair of shoes?
A. 1/144
B. 1/66
C. 1/23
D. 1/12
E. 1/11
= P(dog chooses ANY sock 1st) x P(2nd sock matches the 1st sock)
= 24/24 x 1/23
= 1/23
Answer: C
Cheers,
Brent
- fskilnik@GMATH
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$$\left. \matrix{AAPL wrote:Veritas Prep
Emily keeps 12 different pairs of shoes (24 individual shoes in total) under her bed. If her dog drags out two shoes at random, what is the probability that he drags out a matching pair of shoes?
A. 1/144
B. 1/66
C. 1/23
D. 1/12
E. 1/11
{\rm{Total}}\,\,:\,\,\,C\left( {24,2} \right) = {{24 \cdot 23} \over 2} = 12 \cdot 23\,\,{\rm{equiprobable}}\,\,{\rm{pairs}}\,\,\,\, \hfill \cr
{\rm{Favorable:}}\,\,\,12\,\,{\rm{real}}\,\,{\rm{pairs}}\,\,\left( {{\rm{matches}}} \right) \hfill \cr} \right\}\,\,\,\,\,\, \Rightarrow \,\,\,\,\,? = {{12} \over {12 \cdot 23}} = {1 \over {23}}$$
This solution follows the notations and rationale taught in the GMATH method.
Regards,
Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
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The first shoe can be any shoe, so its probability is 24/24 = 1. However, since the second shoe must match the first shoe, its probability of being chosen is 1/23. Therefore, the probability that the two shoes forming a matching pair is 1 x 1/23 = 1/23.AAPL wrote:Veritas Prep
Emily keeps 12 different pairs of shoes (24 individual shoes in total) under her bed. If her dog drags out two shoes at random, what is the probability that he drags out a matching pair of shoes?
A. 1/144
B. 1/66
C. 1/23
D. 1/12
E. 1/11
OA C
Answer: C
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