Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, a distance of 350 miles. How long does it make him to complete the trip?
A. 4 hours
B. 5 hours
C. 7 hours
D. 10 hours
E. 12 hours
The OA is C.
I think that this is a simple question, I solved it as follow:
We know that rate = dist/time, then we have 350 miles of distance and we have an average rate of 50 mph, hence
time = dist/rate = 350 / 50 = 7 hour. Option C.
Bob drives at an average rate of 50 mph from Berkeley...
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Your solution is perfect!swerve wrote:Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, a distance of 350 miles. How long does it make him to complete the trip?
A. 4 hours
B. 5 hours
C. 7 hours
D. 10 hours
E. 12 hours
The OA is C.
I think that this is a simple question, I solved it as follow:
We know that rate = dist/time, then we have 350 miles of distance and we have an average rate of 50 mph, hence
time = dist/rate = 350 / 50 = 7 hour. Option C.
Cheers,
Brent
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We can use the formula:swerve wrote:Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, a distance of 350 miles. How long does it make him to complete the trip?
A. 4 hours
B. 5 hours
C. 7 hours
D. 10 hours
E. 12 hours
Average = total distance/total time
50 = 350/t
50t = 350
t = 7 hours
Answer: C
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