What is the area of a triangle with the following vertices L(1, 3), M(5, 1), and N(3, 5)?
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What is the area of a triangle
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sudhir3127
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1/2 Abs [ (x1-x2)(y2-y3) - (y1-y2)(x2-x3) ]logitech wrote:What is the area of a triangle with the following vertices L(1, 3), M(5, 1), and N(3, 5)?
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1/2 abs [(-4)(-4) - (2)(2) ]
1/2*12 = 6
D.
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logitech
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Magic formula huh ? Sweat how do you derive this formula ?sudhir3127 wrote:
1/2 Abs [ (x1-x2)(y2-y3) - (y1-y2)(x2-x3) ]
LGTCH
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"DON'T LET ANYONE STEAL YOUR DREAM!"
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sudhir3127
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its one of the formulas to be learnt .. it takes into consideration matrices..logitech wrote:Magic formula huh ? Sweat how do you derive this formula ?sudhir3127 wrote:
1/2 Abs [ (x1-x2)(y2-y3) - (y1-y2)(x2-x3) ]
a 2X2 matrix
1/2 Absolute [ X1 - X2 X2- X3
Y1-Y2 y2-y3 ]
use 2X 2 matrix and solve the above...
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logitech
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Good old determinantsudhir3127 wrote:its one of the formulas to be learnt .. it takes into consideration matrices..logitech wrote:Magic formula huh ? Sweat how do you derive this formula ?sudhir3127 wrote:
1/2 Abs [ (x1-x2)(y2-y3) - (y1-y2)(x2-x3) ]
a 2X2 matrix
1/2 Absolute [ X1 - X2 X2- X3
Y1-Y2 y2-y3 ]
use 2X 2 matrix and solve the above...
x1 y1 1
x2 y2 1
x3 y3 1
Cool.
LGTCH
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"DON'T LET ANYONE STEAL YOUR DREAM!"
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"DON'T LET ANYONE STEAL YOUR DREAM!"
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vivek.kapoor83
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srisl11
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Very handy formula...sudhir3127 wrote:its one of the formulas to be learnt .. it takes into consideration matrices..logitech wrote:Magic formula huh ? Sweat how do you derive this formula ?sudhir3127 wrote:
1/2 Abs [ (x1-x2)(y2-y3) - (y1-y2)(x2-x3) ]
a 2X2 matrix
1/2 Absolute [ X1 - X2 X2- X3
Y1-Y2 y2-y3 ]
use 2X 2 matrix and solve the above...
Thank you Sudhir
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Tryingmybest
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Logitech . check if this works
Area of triangle =sqrt {s(s-a)(s-b)(s-c) }
where s=(a+b+c)/2
a,b,c are sides of triangle.
From given data find the sides and substitute in the formula
we get area 6.
This is handy when coordinates are not given but length of the sides are given.
Area of triangle =sqrt {s(s-a)(s-b)(s-c) }
where s=(a+b+c)/2
a,b,c are sides of triangle.
From given data find the sides and substitute in the formula
we get area 6.
This is handy when coordinates are not given but length of the sides are given.
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vishubn
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Hi SUdhir !its one of the formulas to be learnt .. it takes into consideration matrices..
a 2X2 matrix
1/2 Absolute [ X1 - X2 X2- X3
Y1-Y2 y2-y3 ]
use 2X 2 matrix and solve the above...
If u dont mind can u elaborate more on this ! i mean its a nice method !
but still not able to get the thought process !!vishu
KILL !! DIE !! or BEAT my FEAR !!! de@D END!!
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logitech
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Okay...Are you ready ?vishubn wrote:Hi SUdhir !its one of the formulas to be learnt .. it takes into consideration matrices..
a 2X2 matrix
1/2 Absolute [ X1 - X2 X2- X3
Y1-Y2 y2-y3 ]
use 2X 2 matrix and solve the above...
If u dont mind can u elaborate more on this ! i mean its a nice method !
vishu
https://people.richland.edu/james/lectur ... /area.html
Have fun!
LGTCH
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"DON'T LET ANYONE STEAL YOUR DREAM!"
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"DON'T LET ANYONE STEAL YOUR DREAM!"
I actually use the same method to draw a rectangle around it to solve it. I found this out when I was solving one of the Kaplan problem that it was easier for me to picture that.
good job with the drawing!
good job with the drawing!
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GMATinsight
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Please find the solution as attachedlogitech wrote:What is the area of a triangle with the following vertices L(1, 3), M(5, 1), and N(3, 5)?
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"GMATinsight"Bhoopendra Singh & Sushma Jha
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