If y and x are numbers such that x + y = 17 and 2x - y = 6, what is the value of x/2?
A. 23/6
B. 11/2
C. 23/3
D. 11
E. 23
The OA is A .
Experts, what is the fastest way to solve this PS question? Thanks.
If y and x are numbers such that x + y = 17 . . . .
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- EconomistGMATTutor
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Hello M7MBA.
The fastest way to solve this PS question is adding both equations.
Adding $$x+y=17\ and\ 2x-y=6$$ you will get $$3x=23,\ so\ x=\frac{23}{3}.$$ Now, we only have to divide by 2. Hence, $$\frac{x}{2}=\frac{\frac{23}{3}}{2}=\frac{23}{6}.$$ Then, the correct answer is A .
I hope this explanation may help you.
There are other ways to solve it, but it is the fastest (and easiest).
I'm available if you'd like a follow up.
Regards.
The fastest way to solve this PS question is adding both equations.
Adding $$x+y=17\ and\ 2x-y=6$$ you will get $$3x=23,\ so\ x=\frac{23}{3}.$$ Now, we only have to divide by 2. Hence, $$\frac{x}{2}=\frac{\frac{23}{3}}{2}=\frac{23}{6}.$$ Then, the correct answer is A .
I hope this explanation may help you.
There are other ways to solve it, but it is the fastest (and easiest).
I'm available if you'd like a follow up.
Regards.
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- Jeff@TargetTestPrep
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We can add the two given equations together and we have:M7MBA wrote:If y and x are numbers such that x + y = 17 and 2x - y = 6, what is the value of x/2?
A. 23/6
B. 11/2
C. 23/3
D. 11
E. 23
(x + y = 17)
+ (2x - y = 6)
3x = 23
x = 23/3
Thus, x/2 = (23/3)/2 = 23/6.
Answer: A
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