Hello,
Can you please assist with this:
If grapes are 92% water and raisins are 20% water by weight, then how much did a quantity of raisins, which currently weighs 10 pounds, weigh when all the raisins were grapes? (Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.)
OA: 100 pounds
Thanks a lot for your help - Sri
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Weighted averages - Grapes/Raisins
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gmattesttaker2
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Hi Sri,
As we know only water evaporates, then the weight of non-water substance in grapes and raisins is the same. Thus 0.08*{weight of grapes}=0.8*{weight of raisins} --> 0.08x = 0.8*10 --> x = 100.
Regards,
Tushar
As we know only water evaporates, then the weight of non-water substance in grapes and raisins is the same. Thus 0.08*{weight of grapes}=0.8*{weight of raisins} --> 0.08x = 0.8*10 --> x = 100.
Regards,
Tushar
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GMATGuruNY
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Since raisins are 20% water, the 10 pounds of raisins are composed of 2 pounds of water and 8 POUNDS OF OTHER STUFF.If grapes are 92% water and raisins are 20% water, then how much did a quantity of raisins, which currently weighs 10 pounds, weigh when all the raisins were grapes? (Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.)
A) 25 pounds
B) 46 pounds
C) 92 pounds
D) 100 pounds
E) 146 pounds
Since grapes are 92% water, the 8 POUNDS OF OTHER STUFF in the original grapes must have constituted 8% of the grapes:
8 = (8/100)x
x = 800/8 = 100.
The correct answer is D.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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