[GMAT math practice question]
If a≠b, and $$\frac{a^2}{\left(a-b\right)}=b$$ , which of the following could be a?
A. -1
B. 0
C. 1
D. 2
E. a does not exist
If a≠b, and a2/(a-b)=b, which of the following could be a?
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=>
a^2/(a-b)=b
=> a^2=b(a-b)
=> a^2=ab - b^2
=> a^2 - ab + b^2 = 0
Since a≠b, one of a and b is not zero.
If a ≠0 or b ≠0, a^2 - ab + b^2 cannot be zero for the following reason:
a^2 - ab + b^2 = a^2 - 2a(b/2) + b^2 = a2 - 2a(b/2) + b^2/3 + (3/4)b^2
= ( a - b/2)^2 + (3/4)b^2 > 0
Thus, there is no pair of real numbers (a,b) satisfying the equation a^2 - ab + b^2 = 0.
Therefore, a cannot exist, and the answer is E.
Answer: E
a^2/(a-b)=b
=> a^2=b(a-b)
=> a^2=ab - b^2
=> a^2 - ab + b^2 = 0
Since a≠b, one of a and b is not zero.
If a ≠0 or b ≠0, a^2 - ab + b^2 cannot be zero for the following reason:
a^2 - ab + b^2 = a^2 - 2a(b/2) + b^2 = a2 - 2a(b/2) + b^2/3 + (3/4)b^2
= ( a - b/2)^2 + (3/4)b^2 > 0
Thus, there is no pair of real numbers (a,b) satisfying the equation a^2 - ab + b^2 = 0.
Therefore, a cannot exist, and the answer is E.
Answer: E
Math Revolution
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