In the rhombus, BC=6, AE=4, and angle DAE = 45°...

[swerve]

In the rhombus, BC=6, AE=4, and angle DAE = 45°. AD is the diameter of the circle. If a man started at C and followed around the outer edge of this figure to D, F, A, G, E, B and back to C, approximately how far did he travel?

A. 14 + 27/4*Ï€
B. 14 + 6Ï€
C. 12 + 6Ï€
D. 14 + 9/2*Ï€
E. 12 + 9/2*Ï€

The OA is D.

Please, can any expert explain this PS question for me? I tried to solve it but I can't get the correct answer. I need your help. Thanks.

[GMATWisdom]

In the rhombus, BC=6, AE=4, and angle DAE = 45°. AD is the diameter of the circle. If a man started at C and followed around the outer edge of this figure to D, F, A, G, E, B and back to C, approximately how far did he travel?

A. 14 + 27/4*Ï€
B. 14 + 6Ï€
C. 12 + 6Ï€
D. 14 + 9/2*Ï€
E. 12 + 9/2*Ï€

The OA is D.

Please, can any expert explain this PS question for me? I tried to solve it but I can't get the correct answer. I need your help. Thanks.

Radius of the circle = 3
joining DE we see that AED is a right angled isosceles triangle with
Angle DAE = Angle ADE = 45.
Arc DE = Arc AGE = ½ arc AED.=(1/2)π3=3/2π (Since arc AED is a semicircle with radius 3 )
Since arc DFA is a semicircle with radius 3 therefore DFA arc= π3=3π
Distance travelled stating from C via DFAGEB and back to C
=CD+arcDFA+arcAGE+EB+BC=6+3Ï€+(3/2)Ï€+2+6=14+9Ï€/2
Hence option D