[GMAT math practice question]
The figure shows that \(\triangle\) ABC is an equilateral triangle and ∠HLK = 40. What is the ratio of ∠BJF to ∠DIB?
1) \(\triangle\) HLK is an isosceles triangle with HL=LK.
2) DE is parallel to FG.
The figure shows that ABC is an equilateral triangle and
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- Max@Math Revolution
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Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.
The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. We should simplify conditions if necessary.
Since we have 2 variables (∠BJF and ∠DJB) and 0 equations, C is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.
Conditions 1) & 2) together tell us that ∠BJF = 10° and ∠DIB = 50°.
Since △HLK is an isosceles triangle with HL=LK , we have ∠AMI = ∠KML = (180° - 40°) / 2 = 70°.
Then we have ∠DIB = ∠AIM = 180° – (60° + 70°) = 180° – 130° = 50°.
We also have ∠JLC = ∠MLG = 70° + 40° = 110° and ∠BJF = ∠LJC = 180° – ( ∠JLC + ∠LCJ ) = 180° – (110° + 60°) = 180° – 170° = 10°.
The answer is unique, and conditions 1) and 2) together are sufficient according to Common Mistake Type 2, which states that the number of answers must be only one.
Both conditions 1) & 2) together are sufficient.
Therefore, C is the correct answer.
Answer: C
Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B, or D is the answer. This occurs in Common Mistake Types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D, or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.
The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. We should simplify conditions if necessary.
Since we have 2 variables (∠BJF and ∠DJB) and 0 equations, C is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.
Conditions 1) & 2) together tell us that ∠BJF = 10° and ∠DIB = 50°.
Since △HLK is an isosceles triangle with HL=LK , we have ∠AMI = ∠KML = (180° - 40°) / 2 = 70°.
Then we have ∠DIB = ∠AIM = 180° – (60° + 70°) = 180° – 130° = 50°.
We also have ∠JLC = ∠MLG = 70° + 40° = 110° and ∠BJF = ∠LJC = 180° – ( ∠JLC + ∠LCJ ) = 180° – (110° + 60°) = 180° – 170° = 10°.
The answer is unique, and conditions 1) and 2) together are sufficient according to Common Mistake Type 2, which states that the number of answers must be only one.
Both conditions 1) & 2) together are sufficient.
Therefore, C is the correct answer.
Answer: C
Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B, or D is the answer. This occurs in Common Mistake Types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D, or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
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Should be C. Since unless you know the lines are parallel, you can not use alternate angle property.