What is the value of y?
(1) 3|x2 – 4| = y – 2
(2) |3 – y| = 11
[spoiler]Answer: C[/spoiler]
What is the best way to solve this absolute value DS problem
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Choice 1 is not clear from your post.
But nevertheless since we need to solve for y and there is another variable x choice 1 is not sufficient.
Choice 2
|3 - y| = 11 has two equations
3-y = 11 and
3 -y = -11
This gives two values for y -8 and 14
Hence 2 is not sufficient either
Together they are not sufficient either.
So answer is E.
But nevertheless since we need to solve for y and there is another variable x choice 1 is not sufficient.
Choice 2
|3 - y| = 11 has two equations
3-y = 11 and
3 -y = -11
This gives two values for y -8 and 14
Hence 2 is not sufficient either
Together they are not sufficient either.
So answer is E.
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Sorry for not writing it clearly.
Choice 1 should be this: (1) 3|x^2 – 4| = y – 2
So from choice (1), you can tell that y>2. Since 3|x^2 – 4| must be positive.
So if you combine what this with what you wrote for (2), you get C.
Thanks for your help!
Choice 1 should be this: (1) 3|x^2 – 4| = y – 2
So from choice (1), you can tell that y>2. Since 3|x^2 – 4| must be positive.
So if you combine what this with what you wrote for (2), you get C.
Thanks for your help!
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There is no special way for this question.
As Bourne told there is nothing to do with statement 1 alone given there is x and nothing simplifies.
Statement 2
Result is either -8 or 11
With statement 1 and 2 you need to chose a positive one number so it's 11
As Bourne told there is nothing to do with statement 1 alone given there is x and nothing simplifies.
Statement 2
Result is either -8 or 11
With statement 1 and 2 you need to chose a positive one number so it's 11