xy plane problem on gmat 2.0 exam

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xy plane problem on gmat 2.0 exam

by fangtray » Sun May 13, 2012 2:57 am
In the xy-plane, at what two points does the graph of y = (x+a)(y+b) intersect the x axis?
1. A + b =1
2. The graph intersects the y-axis at (0,-6)

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by ankita1709 » Sun May 13, 2012 3:33 am
If x= 0, y=ab/(1-a)-----(1)
y=0, x= -a -------------(2)

A)a+b=1
if we replace b=1-a in (1) we get y=-a
Hence no particular solution for this equation.

B)Cuts y axis at (0,-6)
It implies ab/(1-a)=-6
ab= -6(1-a)-----(3)
There are two variables and one equation. Hence no solution


But if we combine both of these
replace b=1-a in (3) we get a = -6

which means (C)

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by GMATGuruNY » Sun May 13, 2012 3:48 am
The question should read:

In the xy-plane, at what two points does the graph of y = (x+a)(x+b) intersect the x axis?

I posted an explanation here:

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by sam2304 » Sun May 13, 2012 5:49 am
fangtray wrote:In the xy-plane, at what two points does the graph of y = (x+a)(x+b) intersect the x axis?
y = x^2 + (a+b)x + ab => This is the equation of the curve. Solving for x will the values at which the curve intersects the x axis. Or this is the question rephrased. What are the values of x ?
1. A + b =1
We don't know the value of product ab in the equation - INSUFF
2. The graph intersects the y-axis at (0,-6)
Substitute the point in the eqn, x = 0 and y = -6, we get ab = -6. We don't the value of (a+b) INSUFF

Together we can find the value of x.

IMO C.
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