Hi,
Can someone please show this problem on a graph? It's hard to visualize the solution just by reading the OG explanation. I guessed the best approach here would be to visualize it instead of plugging it into the y=mx+b formula right? Thanks in advance!
****
In the xy plane, if line k has negative slope and passes through the point (-5, r), is the x intercept of line k positive?
1) The slope of line k is -5
2) r>0
OG practice coordinate plane problem
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Redhorsep wrote:Hi,
Can someone please show this problem on a graph? It's hard to visualize the solution just by reading the OG explanation. I guessed the best approach here would be to visualize it instead of plugging it into the y=mx+b formula right? Thanks in advance!
****
In the xy plane, if line k has negative slope and passes through the point (-5, r), is the x intercept of line k positive?
1) The slope of line k is -5
2) r>0
![Image](https://s1.postimage.org/yxcjpnk4/untitled.jpg)
Here you see all the lines with arrows pointing down are the lines having the negative slope. Negative slope means there is a decrease in the value of y for the increase in the value of x.
From statement 1) lets pick a line having negative slope of -5 say the blue line. Since we have no information about the r that is y intercept it can line on x=-5 line from r = -infinity to + infinity so the line might touch the x axis at infinite locations so this is not sufficient.
Statement 2) given r>o but still there is a lot of space from 0 to infinity so still we cannot have one single value of x - intercept. We also dont know the slope sp there is another infinite combinations of these. so insufficient.
Combining the statements will lead to the Statement 20 ie r>0 and slope m = -5 but since we dont know the value of r exactly there will be infinite values of x intercept....
HOPE U UNDERSTOOD...THANKS.....
-
- Master | Next Rank: 500 Posts
- Posts: 105
- Joined: Fri Nov 05, 2010 8:29 pm
- Thanked: 4 times
Redhorsep wrote:Hi,
Can someone please show this problem on a graph? It's hard to visualize the solution just by reading the OG explanation. I guessed the best approach here would be to visualize it instead of plugging it into the y=mx+b formula right? Thanks in advance!
****
In the xy plane, if line k has negative slope and passes through the point (-5, r), is the x intercept of line k positive?
1) The slope of line k is -5
2) r>0
![Image](https://s1.postimage.org/yxcjpnk4/untitled.jpg)
Here you see all the lines with arrows pointing down are the lines having the negative slope. Negative slope means there is a decrease in the value of y for the increase in the value of x.
From statement 1) lets pick a line having negative slope of -5 say the blue line. Since we have no information about the r that is y intercept it can line on x=-5 line from r = -infinity to + infinity so the line might touch the x axis at infinite locations so this is not sufficient.
Statement 2) given r>o but still there is a lot of space from 0 to infinity so still we cannot have one single value of x - intercept. We also dont know the slope sp there is another infinite combinations of these. so insufficient.
Combining the statements will lead to the Statement 20 ie r>0 and slope m = -5 but since we dont know the value of r exactly there will be infinite values of x intercept....
HOPE U UNDERSTOOD...THANKS.....