If points (a, b) and (c, b) (not shown) lie in the coordinate system above, which quadrants contain the line that passes through (a, b) and (c, b)?
(1) a is a positive integer and c is a negative integer.
(2) b is a positive integer.
[spoiler]The OA is B, but I think it's C.[/spoiler] What do people think?
PR DS #9
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It's intuitive that the points (a, b) and (c, b) will lie on the straight line y = b. If you don't understand why, then find the equation of the line that contain these two points.dpatwa wrote:If points (a, b) and (c, b) (not shown) lie in the coordinate system above, which quadrants contain the line that passes through (a, b) and (c, b)?
(1) a is a positive integer and c is a negative integer.
(2) b is a positive integer.
Say the equation is y = mx + k, where m is the slope of the line and k is the y-intercept. Slope of the line will be = (b - b)/(c - a) = 0 => m = 0
Thus, y = k.
Put any of the points on these equation to find the value of k => k = b
Thus equation of the line is y = b
Therefore if b is positive, then quadrant I and II contains the line and if b is negative, then quadrant III and IV contain the line.
Statement 1: a is a positive integer and c is a negative integer.
Nothing about b.
Not sufficient
Statement 2: b is a positive integer.
Quadrant I and II contains the line.
Sufficient
The correct answer is B.
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Thanks, this actually points to something I guess is good to just ask-- so when they say line, it absolutely HAS to be a continuing line unless otherwise specified? I.e. it wasnt'a line segment that was just in quadrant 1 or 2? Is the line only cut off if a boundary is explicitly given?
Thanks again!
Thanks again!