question 1/(2(10)^35
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hi can you please help me with the following question. I have attached it.
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- selango
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(1/5)^m.(1/4)^18=1/2(10)^35
m=?
(1/5)^m.(1/4)^18=1/2.(2.5)^35
(1/5)^m.(1/4)^18=1/2.2^35.5^35
(1/5)^m.(1/4)^18=1/2^36.5^35
(1/5)^m.(1/4)^18=1/4^18.5^35
(1/5)^m.(1/4)^18=1/5^35 . 1/4^18
-->m=35
Pick D
Hope this clarify!!!
m=?
(1/5)^m.(1/4)^18=1/2.(2.5)^35
(1/5)^m.(1/4)^18=1/2.2^35.5^35
(1/5)^m.(1/4)^18=1/2^36.5^35
(1/5)^m.(1/4)^18=1/4^18.5^35
(1/5)^m.(1/4)^18=1/5^35 . 1/4^18
-->m=35
Pick D
Hope this clarify!!!
--Anand--
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selango thank you first of all for fast reply
but I don't understand it fully
from here I dont understand:
(1/5)^m.(1/4)^18=1/2^36.5^35
(1/5)^m.(1/4)^18=1/4^18.5^35
(1/5)^m.(1/4)^18=1/5^35 . 1/4^18
how do you get the 36.5
and the 18.5
and the last one fully dont understand.
sorry for inconvenience
but I don't understand it fully
from here I dont understand:
(1/5)^m.(1/4)^18=1/2^36.5^35
(1/5)^m.(1/4)^18=1/4^18.5^35
(1/5)^m.(1/4)^18=1/5^35 . 1/4^18
how do you get the 36.5
and the 18.5
and the last one fully dont understand.
sorry for inconvenience
- kvcpk
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Well, I think Anand meant . to be * [multiplication][email protected] wrote:selango thank you first of all for fast reply
but I don't understand it fully
from here I dont understand:
(1/5)^m.(1/4)^18=1/2^36.5^35
(1/5)^m.(1/4)^18=1/4^18.5^35
(1/5)^m.(1/4)^18=1/5^35 . 1/4^18
how do you get the 36.5
and the 18.5
and the last one fully dont understand.
sorry for inconvenience
Let me rewrite those for you:
(1/5)^m * (1/4)^18=1/(2^36 * 5^35)
(1/5)^m * (1/4)^18=(1/4)^18 * (1/5)^35
(1/5)^m * (1/4)^18=(1/5)^35 * (1/4)^18
Hence m=35.
Does this help?
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don't be afraid of failure and don't abandon it.
People who work sincerely are the happiest."
Chanakya quotes (Indian politician, strategist and writer, 350 BC-275BC)
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- Junior | Next Rank: 30 Posts
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- Joined: Wed Oct 20, 2010 2:03 am
Well, I think Anand meant . to be * [multiplication]
Let me rewrite those for you:
(1/5)^m * (1/4)^18=1/(2^36 * 5^35)
(1/5)^m * (1/4)^18=(1/4)^18 * (1/5)^35
(1/5)^m * (1/4)^18=(1/5)^35 * (1/4)^18
Hence m=35.
Does this help?[/quote]
thank you for your help,
but the thing what I dont understand is, where do you get the 36 from and the 5 from?
and why do you do in the second one all of a sudden 1/4^18, while in the previous one it was 1/2?
sorry once again
Let me rewrite those for you:
(1/5)^m * (1/4)^18=1/(2^36 * 5^35)
(1/5)^m * (1/4)^18=(1/4)^18 * (1/5)^35
(1/5)^m * (1/4)^18=(1/5)^35 * (1/4)^18
Hence m=35.
Does this help?[/quote]
thank you for your help,
but the thing what I dont understand is, where do you get the 36 from and the 5 from?
and why do you do in the second one all of a sudden 1/4^18, while in the previous one it was 1/2?
sorry once again
- Geva@EconomistGMAT
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I recommend you to read these 2 topics, they are pretty good.
Exponent Manipulation: Tough Questions, Basic Approaches
https://www.beatthegmat.com/mba/2010/05/ ... approaches
The Powers That Be: Solving Tough Exponent Problems
https://www.beatthegmat.com/mba/2009/10/ ... t-problems
Exponent Manipulation: Tough Questions, Basic Approaches
https://www.beatthegmat.com/mba/2010/05/ ... approaches
The Powers That Be: Solving Tough Exponent Problems
https://www.beatthegmat.com/mba/2009/10/ ... t-problems
Usmana..[email protected] wrote:Well, I think Anand meant . to be * [multiplication]
Let me rewrite those for you:
(1/5)^m * (1/4)^18=1/(2^36 * 5^35)
(1/5)^m * (1/4)^18=(1/4)^18 * (1/5)^35
(1/5)^m * (1/4)^18=(1/5)^35 * (1/4)^18
Hence m=35.
Does this help?
The right hand side(RHS) of the equation is 1 / 2 (10)^35. Since 10 = 2*5 the RHS can be rewritten as 1 / 2 (2*5)^35 i.e
1 / 2 * 1 / (2)^35 * 1 / (5)^35. Now multiply 1 / 2 and 1 / (2)^35 to get 1 / (2)^36.
To get to the solution of this problem we need to equate the LHS(left hand side) of the equation to the RHS. Therefore rewrite 1 / (2)^36 as 1 / (4)^18 by splitting 1 / (2)^36 into 1 / (2)^18 * 1 / (2)^18.
To better understand the concepts above please do a chapter on Exponents.
Usmana..[email protected] wrote:Well, I think Anand meant . to be * [multiplication]
Let me rewrite those for you:
(1/5)^m * (1/4)^18=1/(2^36 * 5^35)
(1/5)^m * (1/4)^18=(1/4)^18 * (1/5)^35
(1/5)^m * (1/4)^18=(1/5)^35 * (1/4)^18
Hence m=35.
Does this help?
The right hand side(RHS) of the equation is 1 / 2 (10)^35. Since 10 = 2*5 the RHS can be rewritten as 1 / 2 (2*5)^35 i.e
1 / 2 * 1 / (2)^35 * 1 / (5)^35. Now multiply 1 / 2 and 1 / (2)^35 to get 1 / (2)^36.
To get to the solution of this problem we need to equate the LHS(left hand side) of the equation to the RHS. Therefore rewrite 1 / (2)^36 as 1 / (4)^18 by splitting 1 / (2)^36 into 1 / (2)^18 * 1 / (2)^18.
To better understand the concepts above please do a chapter on Exponents.