How many number of 3 digit numbers can be formed with the digits 0,1,2,3,4,5 if
no digit is repeated in any number? How many of these are even and how many
odd?
Please answer.
P and C hard question
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- chaitanyareddy
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ABC is the 3 digit number we must find and the digits arnt allowed to repeated....chaitanyareddy wrote:How many number of 3 digit numbers can be formed with the digits 0,1,2,3,4,5 if
no digit is repeated in any number? How many of these are even and how many
odd?
Please answer.
A cant be 0 thus A has 5 choices
B =6-1=5 ways to choose from (0,1,2,3,4,5) and we have to - 1 because A was chosen
the same to C=4
total= 5*5*4=100?
even number ABC
C must be even thus C= 3 choices (0,2,4)
A cant be 0 and cant be any number of C thus A can have only 4
C= 4
so total=48?
the same with ABC -odd
whats the answer
- chaitanyareddy
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Yeah even I am getting the same answer. However one doubt is if there are total 100 possible 3 digit numbers and 48 of them are even and 48 of them are odd , then what about the remaining 4 numbers...?
I mean all the three digits numbers able to be formed should be equal to number three digit even + no of three digit odd.
but 100 ≠48 + 48.
Am I missing something here..?
I mean all the three digits numbers able to be formed should be equal to number three digit even + no of three digit odd.
but 100 ≠48 + 48.
Am I missing something here..?
Even the word Impossible says I'Mpossible.
Even#s are 52 and ODD#s are 48.
Since u know the ODS#s let me give u how the EVEN number count comes to 52.
Case 1: Number ending with 0. 5*4 (1st digit can not be 0 so u have 1,2,3,4,5 to select from. 2nd digit can not be 0 and the 1st digit. So u have 4 numbers to select from).
Case 2: Number ending with 2. 4*4
Case 3: Number ending with 4. 4*4
Total = 52.
Since u know the ODS#s let me give u how the EVEN number count comes to 52.
Case 1: Number ending with 0. 5*4 (1st digit can not be 0 so u have 1,2,3,4,5 to select from. 2nd digit can not be 0 and the 1st digit. So u have 4 numbers to select from).
Case 2: Number ending with 2. 4*4
Case 3: Number ending with 4. 4*4
Total = 52.