Quadratic equations: Real solutions
This topic has expert replies
- Rich@VeritasPrep
- GMAT Instructor
- Posts: 147
- Joined: Tue Aug 25, 2009 7:57 pm
- Location: New York City
- Thanked: 76 times
- Followed by:17 members
- GMAT Score:770
>>>
Last edited by Rich@VeritasPrep on Wed Jul 07, 2010 8:06 pm, edited 1 time in total.
Rich Zwelling
GMAT Instructor, Veritas Prep
GMAT Instructor, Veritas Prep
-
- Junior | Next Rank: 30 Posts
- Posts: 13
- Joined: Mon May 31, 2010 6:44 pm
Hi Raz,
The equation |x|^2 - 5|x|+6=0
will rather breaks down to:
(|x| - 2)(|x| - 3) = 0
giving |x| = 2 or |x| = 3
so the equation should have 4 solutions: 2, -2, 3, -3
Am I missing something here??
Thanks!!
The equation |x|^2 - 5|x|+6=0
will rather breaks down to:
(|x| - 2)(|x| - 3) = 0
giving |x| = 2 or |x| = 3
so the equation should have 4 solutions: 2, -2, 3, -3
Am I missing something here??
Thanks!!
- Rich@VeritasPrep
- GMAT Instructor
- Posts: 147
- Joined: Tue Aug 25, 2009 7:57 pm
- Location: New York City
- Thanked: 76 times
- Followed by:17 members
- GMAT Score:770
Nope! Just a misread on my part. You're absolutely correct!
Rich Zwelling
GMAT Instructor, Veritas Prep
GMAT Instructor, Veritas Prep