A team has a record of 12 wins and 13 losses for the season. Three games remain. If the probability of winning each remaining game is 1/2, and there are no draws, what is the probability that the team will finish the season with a winning record ?
1/8
1/4
3/8
1/2
5/8
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heshamelaziry
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crackthetest
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heshamelaziry
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[spoiler]OA 1/8[/spoiler]heshamelaziry wrote:A team has a record of 12 wins and 13 losses for the season. Three games remain. If the probability of winning each remaining game is 1/2, and there are no draws, what is the probability that the team will finish the season with a winning record ?
1/8
1/4
3/8
1/2
5/8
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jaspreet_takhar
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heshamelaziry
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But the team only need ttwo wins to be 14-13 ?jaspreet_takhar wrote:The team needs to win the remaining 3 matches to get a score of 15-13..
so , 1/8 is right
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crackgmat007
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What if the last game is lost? It will be a draw. Since theq uestion requires us to calculate the probability that the team will finish the season with a winning record , all three games need to be considered.heshamelaziry wrote:But the team only need ttwo wins to be 14-13 ?jaspreet_takhar wrote:The team needs to win the remaining 3 matches to get a score of 15-13..
so , 1/8 is right
Hope it clarifies.
Yeah it should be 1/8.
Think about it. The team is has 12 wins, 13 losses. 3 games remain.
If they win 2 and lose 1, their final record will be 14 wins, 14 losses.
So they will need to win of their remaining games. Probablily of that is 1/2 * 1/2 * 1/2 = 1/8.
Think about it. The team is has 12 wins, 13 losses. 3 games remain.
If they win 2 and lose 1, their final record will be 14 wins, 14 losses.
So they will need to win of their remaining games. Probablily of that is 1/2 * 1/2 * 1/2 = 1/8.
