possible values of x ?
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C should be. for any x greater than sqrt(2) and any x less than (-sqrt(2)) the equation will hold good.
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Squaring on both sides of inequality, I got X<sqrt(2). I am not clear about -sqrt(2)<X. Can someone explain this pls?tohellandback wrote:x^2-2<0
X^2<2
-sqrt(2)<X<sqrt(2)
When you take the sq root of a squared variable, you need to take into account that the answer could be positive or negative, so take the absolute value:
x^2 < 2
abs(x) < sqrt2
x < sqrt 2 and -x < sqrt 2 or x > -sqrt2
ans. is C
x^2 < 2
abs(x) < sqrt2
x < sqrt 2 and -x < sqrt 2 or x > -sqrt2
ans. is C