how could I have solved this?

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how could I have solved this?

by abcdefg » Fri Jul 10, 2009 6:51 am
See attached picture. The OA is A. 2. . It involves a lot of clever manipulation. My question is how could I have been known to do these manipulations? Is there a shortcut or a cue that I don't know about? thanks
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by DanaJ » Fri Jul 10, 2009 7:09 am
The fraction can be rewritten as:

15^x + 15^(x + 1) = (4^y) * (15^y)

Deal with the left side first:

15^x + 15^(x + 1) = (15^x) * (1 + 15) = (15^x) * 16 = (15^x) * (4^2)

So you have that:

(15^x)*(4^2) = (4^y)*(15^y) --- since 4^2 has to be equal to 4^y, you get y = 2. This means that:

(15^x)*(4^2) = (4^2)*(15^2) --- divide each side by 4^2 to get

15^x = 15^2 --- x = 2.