In the figure above \(- \angle ABC = \angle ADC = 90^{\circ}.\) Is \(AD > BC?\)

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Q370-e1480320572599.png
In the figure above \(- \angle ABC = \angle ADC = 90^{\circ}.\) Is \(AD > BC?\)

(1) \(\angle CAB = \angle BCA\)
(2) \(CD > AB\)

Answer: B

Source: e-GMAT