Should I pick numbers for this question ? What is the best strategy ?
During a trip on an expressway, Don drove a total of x miles. His average speed on a certain 5 mile section of the expressway was 30 miles an hour , and his average speed for the remainder of the trip was 60 miles per hour. His travel time for the x mile trip was what percent greater than it would have been if he had travelled at a constant rate of 60 miles per hour for the entire trip ?
8.5%
50%
x/12 %
60/x %
500/x %
Ans E
Diatance = Time*Rate
For the 5 mile section Time=1/6 or 10 mins
For the remainder Distance= (x-5) Rate=60 So Time = (x-5)/60 or (x-5)mins
Total time = (x-5)mins + 10 mins
Option 2
Distance = x Rate=60 so Time = x/60 or x mins
This comes down to how much more is x+5 > x ?
I know I am missing something here. PLease help!! Exam is on Monday
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Hi moneyman,
An easier way to look at this problem is to plug in numbers, so how about using 20 for X? With X = 20, Don took 10 minutes if he traveled 5 miles of the total distance at 30 miles/hour, plus 15 minutes for the rest of the trip at 60 miles/hour, for a total of 25 minutes.
However, if he traveled the entire distance at 60 miles/hour, it would only have taken him 20 minutes.
Thus, 25 minutes - 20 minutes = a difference of 5 minutes, and 5/20 = 25% (the difference between the two options). Now, find the answer that gives you this percentage, by plugging in the original number you chose for X (which is 20) and you'll see that the correct answer is choice E.
One last word of advice, no matter how good you are at algebra, you're better at arithmetic; so plug in whenever possible.
Good luck on your exam!
An easier way to look at this problem is to plug in numbers, so how about using 20 for X? With X = 20, Don took 10 minutes if he traveled 5 miles of the total distance at 30 miles/hour, plus 15 minutes for the rest of the trip at 60 miles/hour, for a total of 25 minutes.
However, if he traveled the entire distance at 60 miles/hour, it would only have taken him 20 minutes.
Thus, 25 minutes - 20 minutes = a difference of 5 minutes, and 5/20 = 25% (the difference between the two options). Now, find the answer that gives you this percentage, by plugging in the original number you chose for X (which is 20) and you'll see that the correct answer is choice E.
One last word of advice, no matter how good you are at algebra, you're better at arithmetic; so plug in whenever possible.
Good luck on your exam!
Jim S. | GMAT Instructor | Veritas Prep
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I'd just assume x = 5.
Then for 30 miles per hour on a 5 mile road, he averaged 30 miles per hour. The remaining road is 0 miles so the total average speed is 30 miles per hour.
If he traveled 60 miles per hour on that 5 mile road, then his average speed would be 60 miles per hour. This is double the 30 miles per hour rate.
So I plug in 5 in answer choices to see if I get 100% anywhere. Voila, E is answer.
Then for 30 miles per hour on a 5 mile road, he averaged 30 miles per hour. The remaining road is 0 miles so the total average speed is 30 miles per hour.
If he traveled 60 miles per hour on that 5 mile road, then his average speed would be 60 miles per hour. This is double the 30 miles per hour rate.
So I plug in 5 in answer choices to see if I get 100% anywhere. Voila, E is answer.
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We are given that Don drives a total of x miles, his average speed on a 5-mile section of the expressway was 30 mph, and his average speed for the remainder of the trip, or x - 5, miles was 60 mph.moneyman wrote:Should I pick numbers for this question ? What is the best strategy ?
During a trip on an expressway, Don drove a total of x miles. His average speed on a certain 5 mile section of the expressway was 30 miles an hour , and his average speed for the remainder of the trip was 60 miles per hour. His travel time for the x mile trip was what percent greater than it would have been if he had travelled at a constant rate of 60 miles per hour for the entire trip ?
8.5%
50%
x/12 %
60/x %
500/x %
Since time = distance/rate, the time for the first 5-mile section is 5/30 = 1/6 of an hour and the time for the remainder of the trip is (x-5)/60 hours.
Thus, the total time is 1/6 + (x-5)/60 = 10/60 + (x-5)/60 = (x + 5)/60 hours.
Had he traveled at a constant rate of 60 miles per hour for the entire trip, then his time would have been x/60 hours.
We need to determine the percent by which (x + 5)/60 is greater than x/60.
[(x + 5)/60 - x/60]/(x/60) * 100%
(5/60)/(x/60) * 100%
5/x * 100%
500/x%
Answer:E
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