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The distance between West-Town to East-Town is 15 kilometers

Expert replies
by BTGmoderatorLU » Fri Jun 01, 2018 2:36 pm

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00:00

Answers

A

B

C

D

E

Stats

Difficulty

The distance between West-Town to East-Town is 15 kilometers. Two birds start flying simultaneously towards one another, the first leaving from West-Town at a speed of 4 kilometers per minute and the second bird, leaving from East-Town, at a speed of 1 kilometers per minute. What will be the distance, in kilometers, between the meeting point and West-Town?

A. 3
B. 7
C. 10
D. 12
E. 15

The OA is D.

I get the solution to this PS question as follows,

Time taken by the birds to meet = 15/(4+1) = 3 minutes.

Distance traveled by the bird traveling from West-Town = 4*3 = 12. Option D.

Can anyone explain another way to solve this question? Thanks!
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Source: — Problem Solving |

by GMATGuruNY » Fri Jun 01, 2018 11:14 pm
BTGmoderatorLU wrote:The distance between West-Town to East-Town is 15 kilometers. Two birds start flying simultaneously towards one another, the first leaving from West-Town at a speed of 4 kilometers per minute and the second bird, leaving from East-Town, at a speed of 1 kilometers per minute. What will be the distance, in kilometers, between the meeting point and West-Town?

A. 3
B. 7
C. 10
D. 12
E. 15
Since the two birds travel toward each other, they WORK TOGETHER to cover the 15 kilometers between them.
When elements work together, ADD THEIR RATES.
The combined rate for the two birds = 4+1 = 5 kpm.
Of every 5 kilometers traveled by the two birds working together, 4 kilometers are traveled by the bird leaving from West-Town.
Implication:
The bird leaving from West-Town will travel 4/5 of the 15-kilometer distance:
(4/5)(15) = 12 kilometers.

The correct answer is D.
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by Scott@TargetTestPrep » Tue Jun 12, 2018 10:13 am
BTGmoderatorLU wrote:The distance between West-Town to East-Town is 15 kilometers. Two birds start flying simultaneously towards one another, the first leaving from West-Town at a speed of 4 kilometers per minute and the second bird, leaving from East-Town, at a speed of 1 kilometers per minute. What will be the distance, in kilometers, between the meeting point and West-Town?

A. 3
B. 7
C. 10
D. 12
E. 15
We can use the equation:

Distance 1 + Distance 2 = total distance

4t + 1t = 15

5t = 15

t = 3

Since they meet after 3 minutes, the first bird has flown 12 km from West-Town when it meets the second bird; thus, the distance between the meeting and West-Town is 12 km.

Answer: D

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