x cannot =0

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x cannot =0

by grandh01 » Sat Aug 04, 2012 5:45 pm
If x≠0, what is the value of
(x^p/x^q)^4
(1) p = q
(2) x = 3

Thanks in advance

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by eagleeye » Sat Aug 04, 2012 6:45 pm
grandh01 wrote:If x≠0, what is the value of
(x^p/x^q)^4
(1) p = q
(2) x = 3

Thanks in advance
We need to find x^p/x^q)^4 = (x^(p-q))^4= x^(4(p-q))
Lets check:

(1) p = q
p=q
=> p-q=0.
Then
x^(4(p-q)) = x^0 = 1. Sufficient.
(2) x = 3
x^(4(p-q)) = 3^(4(p-q)). Value of x depends on p-q value. Insufficient.

Hence A is correct :)

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by Anurag@Gurome » Sat Aug 04, 2012 9:10 pm
grandh01 wrote:If x≠0, what is the value of (x^p/x^q)^4
(1) p = q
(2) x = 3

Thanks in advance
(x^p/x^q)^4 = x^(p - q)^4

(1) p = q or p - q = 0
So, x^(p - q)^4 = x^0^4 = x^0 = 1; SUFFICIENT.

(2) x = 3
x^(p - q)^4 = = 3^(p - q)^4 but we do not know the values of p, q or p - q; NOT sufficient.

The correct answer is A.
Anurag Mairal, Ph.D., MBA
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