If abc = b^3, which of the following must be true?
I. ac = b^2
II. b = 0
III. ac = 1
A. None
B. I only
C. II only
D. I and III
E. II and III
[spoiler]OA=A[/spoiler].
I don't understand this PS question. Why is A the correct choice? Can anyone explain this to me? Please.
If abc = b^3 , which of the following must be true?
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Try some numbers
Let B=0, then A*0*C = 0
Test the first possibility: Does A*C have to equal B^2= 0 for the above to be true ? No, A and C could be any number
Second possibility can't be ruled out since we assumed it above
Third possibility: Does A*C = 1. Not necessarily, per the first possibility
Now, try some new numbers to see if B=0 is required
Let A=1, B=1 and C=1. Do these multiplied together = B^3 =1 ? Yes. Is B=0 ?, No. Therefore the second possibility, B=0 isn't necessarily true
Answer None, A
Let B=0, then A*0*C = 0
Test the first possibility: Does A*C have to equal B^2= 0 for the above to be true ? No, A and C could be any number
Second possibility can't be ruled out since we assumed it above
Third possibility: Does A*C = 1. Not necessarily, per the first possibility
Now, try some new numbers to see if B=0 is required
Let A=1, B=1 and C=1. Do these multiplied together = B^3 =1 ? Yes. Is B=0 ?, No. Therefore the second possibility, B=0 isn't necessarily true
Answer None, A
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$$abc=b^3$$
$$b\left(ac-b^2\right)=0$$
$$So,\ it\ is\ either\ b=0,\ or\ ac=b^2$$
Therefore, NONE of the given option is true
if b=0, then 'ac' will be equal to any number which makes option I and III very uncertain.
Also, If 'ac=b^2' then 'b' can also be any number so Option II is also uncertain.
$$b\left(ac-b^2\right)=0$$
$$So,\ it\ is\ either\ b=0,\ or\ ac=b^2$$
Therefore, NONE of the given option is true
if b=0, then 'ac' will be equal to any number which makes option I and III very uncertain.
Also, If 'ac=b^2' then 'b' can also be any number so Option II is also uncertain.
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abc = b^3Gmat_mission wrote:If abc = b^3, which of the following must be true?
I. ac = b^2
II. b = 0
III. ac = 1
A. None
B. I only
C. II only
D. I and III
E. II and III
abc - b^3 = 0
b(ac - b^2) = 0
(b = 0) or (ac - b^2 = 0 ---> ac = b^2)
Since it's either b = 0 or ac = b^2, so neither one is a must true statement. Also, nowhere we can conclude that ac = 1. So none of the statements is a must true.
Answer: A
Jeffrey Miller
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