oops.. just missed the heading..sorry for that..pahwa wrote:I am talking about SIMPLE INETEREST.
To make it more clear,
Amount = P +Interest
= P + (P*R*T/100)
= P[ 1+ (R*T/100)] taking P common.
Compund Interest will be my next post.
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Compund Interest:
1. Amount = P*[1+ (R/(100*n))]^n*t
where,
P = Principle
R = Rate of Interest
T = Time in years
n = Conversion period.
Value of n = 1, if compunded yearly
= 2, if compunded half yearly
= 4, if quaterly
= 12, if monthly.
2. Compund Interest = Amount - P
3. Incase, power is bigger, please use binomial theorem to solve.
1. Amount = P*[1+ (R/(100*n))]^n*t
where,
P = Principle
R = Rate of Interest
T = Time in years
n = Conversion period.
Value of n = 1, if compunded yearly
= 2, if compunded half yearly
= 4, if quaterly
= 12, if monthly.
2. Compund Interest = Amount - P
3. Incase, power is bigger, please use binomial theorem to solve.
Correct me if I'm wrong but diagonals of a rectangle do not form 4 congruent triangles.Rectangle : 1. Diagonals of rectangle bisect each other.
2. Diagonals form four congruent triangle.
I agree .. they form 2 pairs of congruent trianglesjrbrown2 wrote:Correct me if I'm wrong but diagonals of a rectangle do not form 4 congruent triangles.Rectangle : 1. Diagonals of rectangle bisect each other.
2. Diagonals form four congruent triangle.
Here I list the question number from Problem solving section of OG11. These questions are easy. No doubt. But, recommend that you refresh the concepts.
Q26, 46, 64, 88, 121, 129, 196, 206, 217, 248.
My problem areas were Probability and Permutation. So, you would find even a simple questions from this topic in above set. If you are good at these, kindly ignore.
Q26, 46, 64, 88, 121, 129, 196, 206, 217, 248.
My problem areas were Probability and Permutation. So, you would find even a simple questions from this topic in above set. If you are good at these, kindly ignore.
Just know 3 identities and simple relations. That would be enough.
1. (sin)^2 A + (cos)^2 A = 1
2. 1 + (tan)^2 A = (sec)^2 A
3. 1 + (cot)^2 A = (cosec)^2 A
1/ pi = 0.3183
S = r*Q, where, S = length of the arc, r = radius, Q = Angle subtended by the arc.
1. (sin)^2 A + (cos)^2 A = 1
2. 1 + (tan)^2 A = (sec)^2 A
3. 1 + (cot)^2 A = (cosec)^2 A
1/ pi = 0.3183
S = r*Q, where, S = length of the arc, r = radius, Q = Angle subtended by the arc.
There are following theorems. Please note that S => Sides od triangle, A=>Angle of triangle in following discussion.
1. SSS theorem, which says that 2 triangles are congruent if all 3 corresponding sides of one triangle are equal to all 3 corresponding sides of another triangle.
2. SAS => Two sides and included angle of one triangle are equal to Two sides and included angle of another triangle.
3. AAS => Two angles and any one side of one triangle are equal to Two angles and any one side of another triangle.
4. RHL => Corresponding hypotenuese of two right angled triangles are equal and corresponding (leg) side of both triangles are equal.
1. SSS theorem, which says that 2 triangles are congruent if all 3 corresponding sides of one triangle are equal to all 3 corresponding sides of another triangle.
2. SAS => Two sides and included angle of one triangle are equal to Two sides and included angle of another triangle.
3. AAS => Two angles and any one side of one triangle are equal to Two angles and any one side of another triangle.
4. RHL => Corresponding hypotenuese of two right angled triangles are equal and corresponding (leg) side of both triangles are equal.
