BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

TIP OF THE DAY

Expert replies

by gmatrant » Thu Nov 08, 2007 1:00 am
pahwa wrote:I am talking about SIMPLE INETEREST.

To make it more clear,
Amount = P +Interest
= P + (P*R*T/100)
= P[ 1+ (R*T/100)] taking P common.

Compund Interest will be my next post.
oops.. just missed the heading..sorry for that..
Join the discussion

Compund Interest

by pahwa » Tue Nov 13, 2007 7:04 pm
Compund Interest:

1. Amount = P*[1+ (R/(100*n))]^n*t
where,
P = Principle
R = Rate of Interest
T = Time in years
n = Conversion period.

Value of n = 1, if compunded yearly
= 2, if compunded half yearly
= 4, if quaterly
= 12, if monthly.
2. Compund Interest = Amount - P
3. Incase, power is bigger, please use binomial theorem to solve.
Join the discussion

by jrbrown2 » Sat Nov 17, 2007 12:04 am
Rectangle : 1. Diagonals of rectangle bisect each other.
2. Diagonals form four congruent triangle.
Correct me if I'm wrong but diagonals of a rectangle do not form 4 congruent triangles.
Join the discussion

by gabriel » Sun Nov 18, 2007 10:07 pm
jrbrown2 wrote:
Rectangle : 1. Diagonals of rectangle bisect each other.
2. Diagonals form four congruent triangle.
Correct me if I'm wrong but diagonals of a rectangle do not form 4 congruent triangles.
I agree .. they form 2 pairs of congruent triangles
Join the discussion

Here I list the question number from Problem solving section of OG11. These questions are easy. No doubt. But, recommend that you refresh the concepts.

Q26, 46, 64, 88, 121, 129, 196, 206, 217, 248.

My problem areas were Probability and Permutation. So, you would find even a simple questions from this topic in above set. If you are good at these, kindly ignore.
Join the discussion

Trigonometry

by pahwa » Wed Dec 12, 2007 8:42 pm
Just know 3 identities and simple relations. That would be enough.

1. (sin)^2 A + (cos)^2 A = 1
2. 1 + (tan)^2 A = (sec)^2 A
3. 1 + (cot)^2 A = (cosec)^2 A

1/ pi = 0.3183
S = r*Q, where, S = length of the arc, r = radius, Q = Angle subtended by the arc.
Join the discussion

Congruent Triangles

by pahwa » Wed Dec 12, 2007 8:49 pm
There are following theorems. Please note that S => Sides od triangle, A=>Angle of triangle in following discussion.

1. SSS theorem, which says that 2 triangles are congruent if all 3 corresponding sides of one triangle are equal to all 3 corresponding sides of another triangle.

2. SAS => Two sides and included angle of one triangle are equal to Two sides and included angle of another triangle.

3. AAS => Two angles and any one side of one triangle are equal to Two angles and any one side of another triangle.

4. RHL => Corresponding hypotenuese of two right angled triangles are equal and corresponding (leg) side of both triangles are equal.
Join the discussion