I think you are perfectly right. that's what I got as an answer.

4!/2!*2! * 1/5^2*4/5*2 = 6*1/25*16/25=96/625

nice problem,
take care

why are we calculating the probability for ONLY 2 employees to suffer and assuming the rest do not suffer?
cant it be that 2 WILL suffer implies, 3 may also suffer or all the four?
2 WILL suffer =2 WILL NOT suffer? i dnt get this

The problem states what is the probability that out of 4 employees ,2 will suffer from infection..it coudl be any 2 out of the four.

Your solution wud worked if the problem stated "ATLEAST 2"..

hope this clears your point..

Anuu

Yes you almost got it correct. Here is my approach..
this concept is called conditional probability.

Here we are selecting 2 employees and the other two will automatically get selected. HOW?

lets start..

there are 4 employees. now we need to select 2 out of 4.
part-1..... how to select 2 out of 4... simple 4C2 = 6

part 2..... how will 2 employees be selected out of 4.

SS
SS (reverse)
SN
NS
NN
NN (reverse)
(S= suffer , N=Not suffer)

Can there be any other combination..... ??.........NO

Now when you pick SS then NN automatically gets picked. (WHY?? because you can only select 2 employees who will suffer from disease as per question)
similarly when you pick SN then ..... NS /SN
when..........SS then .....NN

now probability of Suffer is 1/5 and probability of not suffer is 4/5
hence in each case irrespective of the position of N or S the total probability will be
1/5 * 1/5 * 4/5 * 4/5= 16/625
hence total probability will be 6* 16/625 = 96/625

some books also call it conditional probability of events occurring p times in t sequence..

tCp * (PROB OF EVENT A)^P * (PROB OF EVENT B)^t-p

AGAIN I WOULD RECOMMEND THE LONGER WAY FOR THE STARTERS. you can derive this result from the above solution too.

Hope it helps...