11. Which of the following procedures is always equivalent to adding 5 given numbers and then dividing the sum by 5 ?
I. Multiplying the 5 numbers and then finding the 5th root of the product.
II. Adding the 5 numbers, doubling the sum, and then moving the decimal point one place to the left.
III. Ordering the 5 numbers numerically and then selecting the middle number.
(A) None
(B) I only
(C) II only
(D) III only
(E) I and III
Hi,
I though the answer is D) but actually C) is the answer -- can anyone help?
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test31 #11
This topic has expert replies
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rajeshvellanki
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pretty simple man... 1/5=0.2
option 3 is median and what they gave is mean.. so mean <> median.
2(a+b+c+d+e) and moving decimal place by 1 is nothing but 1/5=0.2
Hope you got it.
So answer is C.
R
option 3 is median and what they gave is mean.. so mean <> median.
2(a+b+c+d+e) and moving decimal place by 1 is nothing but 1/5=0.2
Hope you got it.
So answer is C.
R
-
Cybermusings
- Legendary Member
- Posts: 559
- Joined: Tue Mar 27, 2007 1:29 am
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It's simple man...
When u pick 5 numbers say x,y,z,u,v
Sum = (x+y+z+u+w)
Sum / 5 = Mean
Now if you double the mean i.e 2S, the result will stay unchanged if you multiply the denominator or the number 5 with 2
So 2S/5*2 = S/5
Hence II is correct
III for sure is wrong
The only answer which fits here is C
When u pick 5 numbers say x,y,z,u,v
Sum = (x+y+z+u+w)
Sum / 5 = Mean
Now if you double the mean i.e 2S, the result will stay unchanged if you multiply the denominator or the number 5 with 2
So 2S/5*2 = S/5
Hence II is correct
III for sure is wrong
The only answer which fits here is C
