While on a straight road, car X and car Y are traveling at different constant rates. If car X is now 1 mile ahead of car Y, how many minutes from now will car X be 2 miles ahead of car Y?
(1) Car X is traveling at 50 miles per hour and car Y is traveling at 40 miles per hour.
(2) 3 minutes ago car X was 1/2 mile ahead of car Y.
OA is D.
I guessed it right, based on the following calculations
For Statement 1 i used the relative speed formula i.e. relative speed is (u-v) when the 2 objects are traveling in the same direction.
Time= Distance / Speed
Time= (1 mile to cover in order to be 2 miles ahead)/|50-40|
Time= 1/10 hrs i.e. 6 mins. SUFFICIENT.
For Statement 2, I picked up on the phrase "traveling at different constant rates".
Therefore, if the car was 1/2 mile ahead 3 minutes ago (say t1=0), and is 1 mile ahead now (say t2= 3), it shall be 2 miles ahead after t3= 2*t2= 6. SUFFICIENT.
I assumed that since the variable (speed) is constant, the distance will keep doubling after every 3 mins as suggested by distance covered after t1 and t2. Am i correct?
(1) Car X is traveling at 50 miles per hour and car Y is traveling at 40 miles per hour.
(2) 3 minutes ago car X was 1/2 mile ahead of car Y.
OA is D.
I guessed it right, based on the following calculations
For Statement 1 i used the relative speed formula i.e. relative speed is (u-v) when the 2 objects are traveling in the same direction.
Time= Distance / Speed
Time= (1 mile to cover in order to be 2 miles ahead)/|50-40|
Time= 1/10 hrs i.e. 6 mins. SUFFICIENT.
For Statement 2, I picked up on the phrase "traveling at different constant rates".
Therefore, if the car was 1/2 mile ahead 3 minutes ago (say t1=0), and is 1 mile ahead now (say t2= 3), it shall be 2 miles ahead after t3= 2*t2= 6. SUFFICIENT.
I assumed that since the variable (speed) is constant, the distance will keep doubling after every 3 mins as suggested by distance covered after t1 and t2. Am i correct?
Thanks,
Bharat.
Bharat.
