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Triangle DS Problem

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Triangle DS Problem

by mlaboda » Sun Nov 22, 2009 6:29 pm
Thank you for helping me understand this problem!


In the attached figure, the measure of angle PRS is how many degrees greater than the measure of angle PQR?

1. The measure of angle QPR is 30 degrees.
2. 2. The sum of the measures of angles PQR and PRQ is 150 degrees.

Ans. D
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by ershovici » Mon Nov 23, 2009 1:33 am
let agnle PQR is Y, angle PRS is X, we need to find X-Y
ST 1. given taht QPR is 30 degrees, we can make equotion to calculate angle RPS
180 - Y - 30 - 90=180-X-90
-Y-30=-X
-X+Y=-30
X-Y=30

ST 2. given that PQR+PRQ=150 degrees, we find that QPR = 30, the same as for ST1.

So D is the answer.
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