$1200 is invested at a given interest rate for two years. The difference between the simple 2-year non-compounded return at the end of the two years and an annually compounded return is $132. What is the interest rate?
a. 10%
b. 11%
c. 12%
d. 13%
e. 14%
Interest comparison
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- karthikpandian19
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10% simple : 120+120 = simple 2-year non-compounded return at the end of the two years = 240
Using A:10% compound: Principal = 1200(1.1)^2 = 1452 (252)
Using C: 1200(1.12)^2 = 1506 (306 - 144*2)
Assumption: 252-120 = 132.. I got 10% but I read the question wrong or is there a mistake with question.
Using A:10% compound: Principal = 1200(1.1)^2 = 1452 (252)
Using C: 1200(1.12)^2 = 1506 (306 - 144*2)
Assumption: 252-120 = 132.. I got 10% but I read the question wrong or is there a mistake with question.
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HSPA.
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HSPA.
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let i be interest
CI accumulated for two years = 1200(1+i)^2 - 1200
SI for two years = 1200*i*2
difference = 132
1200(1+i)^2-1200 -1200*i*2= 132
1200(i^2) = 132
i^2 = 11/100
i = root(11)/10
i as % = 10root(11)
I think choices are not correct.
user123321
CI accumulated for two years = 1200(1+i)^2 - 1200
SI for two years = 1200*i*2
difference = 132
1200(1+i)^2-1200 -1200*i*2= 132
1200(i^2) = 132
i^2 = 11/100
i = root(11)/10
i as % = 10root(11)
I think choices are not correct.
user123321
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Want to do it right the first time.
Want to do it right the first time.
- karthikpandian19
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The answer choices are correct
Correct answer is [spoiler]A-10%[/spoiler] as per Grockit GMAT
Correct answer is [spoiler]A-10%[/spoiler] as per Grockit GMAT
user123321 wrote:let i be interest
CI accumulated for two years = 1200(1+i)^2 - 1200
SI for two years = 1200*i*2
difference = 132
1200(1+i)^2-1200 -1200*i*2= 132
1200(i^2) = 132
i^2 = 11/100
i = root(11)/10
i as % = 10root(11)
I think choices are not correct.
user123321
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It seems that the Question is not perfectly phrased. Is it the same Question wording as in Grockit GMAT??karthikpandian19 wrote:The answer choices are correct
Correct answer is [spoiler]A-10%[/spoiler] as per Grockit GMATuser123321 wrote:let i be interest
CI accumulated for two years = 1200(1+i)^2 - 1200
SI for two years = 1200*i*2
difference = 132
1200(1+i)^2-1200 -1200*i*2= 132
1200(i^2) = 132
i^2 = 11/100
i = root(11)/10
i as % = 10root(11)
I think choices are not correct.
user123321
Now As Karthik Says the answer is 10%, i feel that question needs to be rephrased. It should be
Difference between the SI added once in 2 years and CI compounded annually then According the the Question
SI would be 120 in 2 years as Interest would be added once in 2 years.
CI would be 120 + 132 ( first and second year ) componded annually.
CI-SI =132?? Therefore [spoiler]A ( 10% )[/spoiler]
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