Problem Solving

In the xy-coordinate system, what is the slope of the line that goes through the origin and is equidistant from the two points P = (1, 11) and Q = (7, 7)?

a) 2
b) 2.25
c) 2.50
d) 2.75
e) 3

y=mx
line must pass through prependicular bisector of PQ
mid point = 4,9
thus slope = 9/4
IMO B

aatech wrote:In the xy-coordinate system, what is the slope of the line that goes through the origin and is equidistant from the two points P = (1, 11) and Q = (7, 7)?

a) 2
b) 2.25
c) 2.50
d) 2.75
e) 3

I understood the dubts raised by some members.
So let me clarify that all the lines passing through the midpoint
of two different points X and Y shall be equidistant from these points X and Y.
From all such lines we have to select only that line which passes through the origin also and find its slope.
Since midpoint is [(1+7)/2,(11+7)/2] i.e. (4,9) ,
we have to find slope of the lone passing through (4,9) and origin that is (0,0)
the slope is =9/4= 2.25
Hence option B is correct.
Hope this clarifies all the doubts raised by some members.