number

This topic has expert replies
Legendary Member
Posts: 876
Joined: Thu Apr 10, 2008 8:14 am
Thanked: 13 times

number

by ketkoag » Sun May 10, 2009 3:24 am
Find the fourth consecutive even number:
(I) The sum of the last two numbers is 30
(II) The sum of the first two numbers is 22

User avatar
Legendary Member
Posts: 682
Joined: Fri Jan 16, 2009 2:40 am
Thanked: 32 times
Followed by:1 members

Re: number

by Vemuri » Sun May 10, 2009 4:39 am
IMO D

Let the 4 consecutive numbers be a, a+2, a+4, a+6

Stmt1: Sum of last 2 numbers, i.e. (a+4) + (a+6) = 30 ==> 2a+10 = 30 ==> a = 10. So, the fourth even number is a+6 ==> 16. Sufficient.

Stmt2: Sum of first 2 numbers, i.e. a + (a+2) = 22 ==> 2a+2 = 22 ==> a = 10. So, the fourth even number is a+6 ==> 16. Sufficient.

Newbie | Next Rank: 10 Posts
Posts: 6
Joined: Tue Mar 31, 2009 3:15 am

by kic883 » Sun May 10, 2009 5:27 am
I think the answer is B.

1) We don't know no. of item in the sequence, so we couldn't calulate the fouth item.

Insufficient

2) The sum of the first two numbers is 22,
10+12=22

the forth item is 16

Sufficient

IMO B

Legendary Member
Posts: 876
Joined: Thu Apr 10, 2008 8:14 am
Thanked: 13 times

Re: number

by ketkoag » Sun May 10, 2009 5:38 am
Vemuri wrote:IMO D

Let the 4 consecutive numbers be a, a+2, a+4, a+6

Stmt1: Sum of last 2 numbers, i.e. (a+4) + (a+6) = 30 ==> 2a+10 = 30 ==> a = 10. So, the fourth even number is a+6 ==> 16. Sufficient.

Stmt2: Sum of first 2 numbers, i.e. a + (a+2) = 22 ==> 2a+2 = 22 ==> a = 10. So, the fourth even number is a+6 ==> 16. Sufficient.
please explain, how do we know the no. of numbers are there in the sequence.

User avatar
Legendary Member
Posts: 682
Joined: Fri Jan 16, 2009 2:40 am
Thanked: 32 times
Followed by:1 members

Re: number

by Vemuri » Sun May 10, 2009 6:43 am
ketkoag wrote: please explain, how do we know the no. of numbers are there in the sequence.
I am making a lot of silly mistakes today. My bad. I agree with kic883's explanation. The answer should be B.