Is the range of integers 8,2,x,4,5 & y greater than 9??
a) y > x+3
b) y > x > 7
No OA for this too........
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naren_nayak
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I think the answer is C.
a) You could have
x=1, y=4: 1 2 4 5 5 8 => Range = 7, which is < 9
OR x=9, y=13: 2 4 5 8 9 13 => Range = 10, which is > 9
Hence A is insufficient.
b) You could have
x=8,y=12: 2 4 5 8 8 12 => Range = 10, which is > 9
OR x=8, y=9: 2 4 5 8 8 9 => Range = 7, which is < 9
Hence B is insufficient
If you considered both together, the sequence with the lowest range is
x=8, y=12: 2 4 5 8 8 12 => Range = 10, which is > 9
Hence C.
a) You could have
x=1, y=4: 1 2 4 5 5 8 => Range = 7, which is < 9
OR x=9, y=13: 2 4 5 8 9 13 => Range = 10, which is > 9
Hence A is insufficient.
b) You could have
x=8,y=12: 2 4 5 8 8 12 => Range = 10, which is > 9
OR x=8, y=9: 2 4 5 8 8 9 => Range = 7, which is < 9
Hence B is insufficient
If you considered both together, the sequence with the lowest range is
x=8, y=12: 2 4 5 8 8 12 => Range = 10, which is > 9
Hence C.
