Search found 273 matches
http://s11.postimage.org/vhkl4hgfz/Screen_Shot_2012_11_05_at_5_07_45_PM.jpg This is the OA, how can they assume that if v<0 then -v/u(u+v) > 0 ? Thanks Notice that we know that we know from the stem that U is positive, and from Statement (1) that (u+v) is positive. That means that in the fraction -...
- by Whitney Garner
Mon Nov 05, 2012 2:17 pm- Forum: Data Sufficiency
- Topic: If u(u+v)
- Replies: 10
- Views: 5093
If each term in the sum A1+A2+...An is either 7 or 77 and the sum equals 350, which of the following could be equal to n ? a) 38 b) 39 c) 40 d) 41 e) 32 Hi bobdylan! Another great way to solve this problem is to think about "hidden" constraints when you have only 1 equation and 2 variable...
- by Whitney Garner
Mon Oct 29, 2012 10:57 am- Forum: Problem Solving
- Topic: Sequence Problem-Gmat Prep
- Replies: 3
- Views: 1611
Hi Whitney, I know this a very basic question but I could definitely do with some help :( Hmm... why is it that we've considered two cases for x (-ve and +ve)? Isn't that clear by the equation that says that it's >1 or >0 (after re-arrangin'). I know that this may be the dumbest question ever but y...
- by Whitney Garner
Sun Oct 21, 2012 12:14 pm- Forum: Problem Solving
- Topic: Inequality Clarification
- Replies: 7
- Views: 2474
Is the integer x divisible by 24? (1) x is divisible by 8. (2) x is divisible by 6. The solution is easy. However, I have some conceptual doubts related to this problem. To solve the problem we have to find the LCM, which is 24 in this question. Therefore, x is divisible by 24. But what about the n...
- by Whitney Garner
Wed Oct 17, 2012 11:45 am- Forum: Data Sufficiency
- Topic: Divisibility and LCM
- Replies: 1
- Views: 1076
The question actually says- the probability of getting atleast 1 PAIR. Hi nidhis.1408! If the problem was correctly transcribed as: If six coins are flipped simultaneously, the probability of getting at least one pair is closest to... Then I would be very skeptical of the source for a couple of rea...
- by Whitney Garner
Wed Oct 17, 2012 11:14 am- Forum: Problem Solving
- Topic: six coins
- Replies: 6
- Views: 1552
This is the solution in Veritas prep- Solution: A. g(f(100)) = g(100!) = the product of all the digits of whatever 100! equals. Since 100! is 100 times some integer, it will certainly end in (at least) two zeros. Even one of those zeros would be sufficient to render the product of all the digits 0,...
- by Whitney Garner
Wed Oct 17, 2012 10:39 am- Forum: Problem Solving
- Topic: factorial
- Replies: 8
- Views: 1912
What does " first shift has 3/4 as many employees" mean is it the 1st shift has 3/4 of total employees? Hey Satya! It actually means that this question wasn't written up to GMAT standards! If this were on the real test (or written by an official source), it would read: "At a certain ...
- by Whitney Garner
Wed Oct 17, 2012 10:32 am- Forum: Problem Solving
- Topic: factory worker
- Replies: 5
- Views: 1706
If n = 14,444, which of the following operations will not yield a number that is divisible by 11? a. n - 1 b. n + 10 c. n - 100 d. n + 100,000 c. n - 100,000 Is there a quick way to solve this? Hi nidhis.1408! I don't know that this is really QUICK, but it is faster than long division! Also, I beli...
- by Whitney Garner
Wed Oct 17, 2012 10:28 am- Forum: Problem Solving
- Topic: divisible by 11
- Replies: 8
- Views: 4299
The OE provided states that |xy|>x^2y^2===>(x^2)(y^2)>(x^4)(y^4)===>1>x^2y^2 Can anyone explain how |xy|>x^2y^2===>(x^2)(y^2)>(x^4)(y^4)? Hi greenwich! This actually uses a little-known definition of absolute value: |x| = sqrt(x^2). So if we redefine the original expression using the following: htt...
- by Whitney Garner
Wed Oct 17, 2012 10:14 am- Forum: Data Sufficiency
- Topic: Is |xy| > x^2y^2 ?
- Replies: 3
- Views: 3524
If six coins are flipped simultaneously, the probability of getting at least one pair is closest to: a. 3% b. 6% c. 75% d. 94% e. 97% Hi nidhis.1408! I'm going to assume that you mean "the probability of getting at least one HEAD " ", because otherwise the probability is CERTAIN (100...
- by Whitney Garner
Wed Oct 17, 2012 10:08 am- Forum: Problem Solving
- Topic: six coins
- Replies: 6
- Views: 1552
A square wooden plaque has a square brass inlay in the centre, leaving a wooden strip of uniform width around the brass square. If the ratio of the brass area to the wooden area is 25 to 39, which of the following could be the width in inches of the woooden strip? A) 1 B) 3 C) 4 i) A only ii) B onl...
- by Whitney Garner
Wed Oct 17, 2012 10:00 am- Forum: Problem Solving
- Topic: PROBLEM IN SOLVIN!!!! PS!! Plzzzzz help asap...
- Replies: 3
- Views: 1170
Q) How many times would 3 appear in all the numbers from 255 to 432 (both inclusive) ? How can i find that ? Hi sohailmbaprep! Just to verify, are you asking how many multiples of 3 are in this list, OR if we factored every number in this list, how many 3s would we have total? For example, if I had...
- by Whitney Garner
Wed Oct 17, 2012 6:36 am- Forum: Problem Solving
- Topic: How many 3s ?
- Replies: 2
- Views: 2680
ok this is going to be kinda wierd... But ill b glad if someone could help me by plugging in as i know some what how to do it but m confused between 2 choices... So here is the question... &^ *^& _____ The product of the two digit numbers above is a three digit number "&@&"...
- by Whitney Garner
Wed Oct 17, 2012 6:32 am- Forum: Problem Solving
- Topic: WIerd PS question
- Replies: 6
- Views: 1046
Hi humpback!humpback wrote:if x=5 in the equation 3y=4x, y is how much greater then x
If x = 5, we just substitute this into the other equation...
3y = 4(5)
3y = 20
y = 20/3.
So how much greater is y than x just translates to y-x = ?
20/3 - 5 = 20/3 - 15/3 = [spoiler]5/3[/spoiler].
Hope this helps!
Whit
- by Whitney Garner
Sun Oct 14, 2012 6:06 pm- Forum: Data Sufficiency
- Topic: 3y=4x
- Replies: 1
- Views: 4237
Can someone explain the ruled used on the bold line? I do not recall how this factoring works. Thank you! 4^17 - 2^28 Understood = (2²)^17 - 2^28 Understood = 2^34 - 2^28 Do not understand the factoring here= 2^28(2^6 - 1) Understood = 2^28(63) Understood = 2^28(7 * 3^2) Therefore, the greatest pr...
- by Whitney Garner
Sun Oct 14, 2012 6:04 pm- Forum: Problem Solving
- Topic: 4^17 - 2^28 Greatest Prime Factor
- Replies: 3
- Views: 1052