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(1) 5^(k-1)>3,000 <5>3,000 <5>15,000 so is enough to answer the question, SUFF

(2) 5^(K-1)=(5^k)-500 <-> (5^k)*(1/5)=(5^k)-500 <-> 5^k=5^(k+1)-2,500 <-> 5^k-5^(k+1)=-2,500 <-> 5^k(1-5)=-2,500 <-> 5^k=625, enough to answer the question, SUFF

Ans is D

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Sure beeparoo, in B setence is incomplete. Waiting for more information

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Hi Yakiraz,

A) You can chose 0, 1, 2 or 3 diferent dressings.

If you choose 0, you have only 1 way to dress the meal

If you choose 1, you have 4 ways (or 4C1).

If you choose 2, you have (4C2)

If you choose 3, you have (4C3)

So 1+4+6+4 = 15

OA?

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Re: Combinatorics

In how many ways can the letters of the word "COMPUTER" can be arranged so that vowels occupy the even positions ? None- you don't have enough vowels- at least, if we need to use all eight letters. We have only 3 vowels and 4 'even positions' to fill (2nd, 4th, 6th and 8th). Where is this...

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senthil wrote:I would go for B

How do you know that experienced readers made fewer mistakes than beginning readers? That is not stated on the text. It says that for experienced readers the order didn't matter, but for begginers yes it matters.

IMO C

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yep, B for me too

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C for me too.

Pls post OA

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Re: need help with method...

[quote="shipra"]If x is not = y, is (x-y)/(x+y) > 1?

1. x>0
2. y<0

can sum1 pls help me with the method to do such questions...please?[/quote]

(x-y)/(x+y)>1 <-> x-y>x+y <-> -2y<0 <-> y>0 so (2) is SUFF

Answer B