Search found 148 matches
Very easy question We are told that 1.0 there are 800 students 2.0 250 live on campus and are more than 20 years old Lets look at the statements separately Statement I : 640 are more than 20 yrs , so from this we only know that 160 are less than 20 and 250 of them live on campus Statement II : 60 ar...
- by ghacker
Sun Aug 09, 2009 7:52 pm- Forum: Data Sufficiency
- Topic: 800 students
- Replies: 2
- Views: 1170
Very easy question Answer is B Y ? In statement I it gives only a ratio so we cannot use it to find the actual figures Look at statement II If one more person joins and the cost is shared equally , then they have to pay less , and the amount is given which is $15 so that actually tells you the total...
- by ghacker
Sun Aug 09, 2009 7:41 pm- Forum: Data Sufficiency
- Topic: rent a car
- Replies: 2
- Views: 1202
Very simple question
Answer is B
Odd number of negatives = a negative result
Why is A not the answer
Take the set as { -1,-3} you get an odd number but the number of elements is even
- by ghacker
Sun Aug 09, 2009 7:34 pm- Forum: Data Sufficiency
- Topic: M is a finite
- Replies: 2
- Views: 871
Ur taking the direct proportionality as an indirect one
Rate = K [A]^2
and Rate = K'/
Or Rate = R[A]^2/
So this means
R[A']^2 /[2B] = R[A]^2/
or [A'] = root2*[A]
[A'] = 1.41[A]
so its a 40% increase
- by ghacker
Sun Aug 09, 2009 7:19 pm- Forum: Problem Solving
- Topic: GMAT Prep - Directly proportional
- Replies: 1
- Views: 4814
The greatest common factor of 16 and the positive integer n is 4, and the greatest common factor of n and 45 is 3. Which of the following could be the greatest common factor of n and 210? If the GCF of 16 and n is 4 the maximum number of 2s that n can have is 2 (4=2^2) If the GCF of n and 45 is 3 th...
- by ghacker
Sun Aug 09, 2009 7:03 pm- Forum: Problem Solving
- Topic: GCF
- Replies: 3
- Views: 2248
Since we are taking about Equilateral Triangles and Squares ; If we are given the area we can find the length of a side and If we know the lengths ( actual lengths or the ratio of lengths ) we know the ratio of the perimeters If we know the ration then we know which one is the larger one So both Sta...
- by ghacker
Tue Jul 28, 2009 6:31 am- Forum: Data Sufficiency
- Topic: Equilateral triangle
- Replies: 5
- Views: 1835
The answer is D
To find the additional amount we have to simplify x{(T-[T-S])}/(t(T-S))
When simplified the answer is D
- by ghacker
Tue Jul 28, 2009 6:25 am- Forum: Problem Solving
- Topic: gmat prep question
- Replies: 15
- Views: 8128
For any integer k from 1 to 10, inclusive, the kth of a certain sequence is given by [(-1)^(k+1)]*(1 / 2^k). If T is the sum of the first 10 terms of the sequence, then T is: It has two parts (i) (-1)^(k+1) we see that the answer will be +1 when k is odd and -1 when k is even Why ? (-1) ^even = +1 a...
- by ghacker
Mon Jul 27, 2009 2:09 pm- Forum: Problem Solving
- Topic: GMAT PREP QUESTION w/OA
- Replies: 11
- Views: 6092
Number of cases infected must be an integer ( assuming that we can divide the cases only in to two parts , those who have got it and those who have not got it )
So it must be a multiple of 0.85 , hence the answer is 17
- by ghacker
Mon Jul 27, 2009 1:33 pm- Forum: Problem Solving
- Topic: Epidemic [need explanation]
- Replies: 2
- Views: 1556
what is the the value of n? 5^21 x 4^11 = 2 X 10^n The important thing here is 10 can be written as 2*5 The L.H.S = R.H.S of the equation so if you look carefully you can see that we can make tens using the 5's and the 4's ( 4=2*2) The limiting factor here is the number of 5's so the maximum power ...
- by ghacker
Mon Jul 27, 2009 1:26 pm- Forum: Problem Solving
- Topic: help with a problem
- Replies: 2
- Views: 1212
14420 is divisible by 14 so is 14406 then we can write 14406 as amultiple of 14
That is 14406 = 14K for some integer K
14414*14416*14418 /14 =(14K+8)(14K+10)(14K+12)/14
= (14(z)+8*10*12)/14 = Z+8*10*12/14
so the remainder is 8
- by ghacker
Mon Jul 27, 2009 1:20 pm- Forum: Problem Solving
- Topic: Number theory
- Replies: 7
- Views: 3984
the question is about factors
So factorize 88,000
88,000 = 88*1000 = 2^3*11*5^3*2^3 = 2^6*5^3*11
But purple is greater than 5 and less than 11 so it should be 8
Why 8 = 2^3 so 2^6 = 8^2
Hence ans= 2
- by ghacker
Mon Jul 27, 2009 1:09 pm- Forum: Problem Solving
- Topic: Hard MGMAT question
- Replies: 15
- Views: 3655
- by ghacker
Wed Jul 22, 2009 10:32 am- Forum: Problem Solving
- Topic: Any other way for this problem?
- Replies: 6
- Views: 1313
Answer is It could be I or II
Understand this is a could be question not a must be one
X= 0.1 then X^2<2X<1/X , is satisfied so I is OK
X = 0.9 then X^2 < 1/X < 2X is satisfied so II is OK
- by ghacker
Wed Jul 22, 2009 10:26 am- Forum: Problem Solving
- Topic: Gmat prep1 ps1
- Replies: 6
- Views: 1408
This is easy ,
The answer should be odd so it cannot be B
consecutive odd integers are in a AP
and the average is 534 so we know the 9th value ( =533)
Hence the smallest or the first value ( in ascending order ) is
first + 16 = 533 ; first = 517
- by ghacker
Wed Jul 22, 2009 10:20 am- Forum: Problem Solving
- Topic: Averages
- Replies: 4
- Views: 4649