J N wrote:from veritas (problem 56 book 4 pg 189)

making a silly mistake somewhere

if 5 * (125)^(1/3) = 1 / (5^(1/x)) then x=?

5*5*5^(1/x) = 1

5^(1+1+(1/x)) =1

2 +(1/x) = 0

x= -1/2



answer is -4

n=4p.
n=2*2*p
As p is a prime above 2 , it doesn't have any even divisors.
Even divisors of n:
2, 4, 2p, 4p
Ans C

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Difference between x and x² can be 2 only when x = -1 or x = 2

Statement 1:
If x=-1, |x-x²| = |-1-1| = 2.
If x=2, |x-x²| = |2-4| = 2. NOT SUFFICIENT (x can be -1 or 2)
Statement 2:
If x=-1, |x²-|x|| = |1-1| = 0.
If x=2, |x²-|x|| = |4-2| =2. SUFFICIENT (x can be 2 only)

B

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