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I gave TOEFL on 9th July and scored a 108.My speaking score is 23.I heard few colleges have this sectional cutoff thing. So just wanted to know how bad is 23 on speaking section and how does it affect my apps?
Congrats Prachi. Great score and all the best wid ur apps.
- by jaxis
Mon Mar 21, 2011 8:03 am
- Forum: I just Beat The GMAT!
- Topic: A date with GMAT on valentines's day:700 (Q50,V35)--AWA 5.0
- Replies: 15
- Views: 6286
The way you see it is right. Another approach: _5_2_1_1_5_ SO this is the situation here.And the relative positions of already present digits doesnt change. now we can select 2 places for the missing 3's in 6c2 ways. = 15 ways. AND No of cases in which both 3's come togather = 6 33 5 2 1 1 5 5 33 2 ...
Congrats Bblast. looks lik ur gonna geta good score.
i also heard that not many ppl take the test in small towns which obviously is a good thing.
less ppl taking the test = less noise
Im planning to take in a month.wht d u suggest.
If n and k are integers and (-2) n^5 > 0, is k^37 < 0?  (n k)^z > 0, where z is an integer that is not divisible by 2.  k < n. http://www.platinumgmat.com Since (-2) n^5 > 0, n^5 is is negative => n is negative. 1) Z is odd.(as it is integer and not divisible by 2) (nk)^Z >0 =>nk is positive ...
Since they both take same time to reach their starting point , the ratio of their speeds will be ratio of the distance travelled. http://s2.postimage.org/2wi66p8f8/Track1.jpg Distance travelled by A = 12R (perimeter of rectangle.) Distance travelled by B = 4 Ï€ R Speeds of A : Speed of B = 12R:4Ï€R ...
A chemical plant has four tanks (A, B, C and D), each containing 1000 litres of a chemical. The chemical is being pumped from one tank to another as follows: From A to B @ 20 litres/minute From C to A @ 90 litres/minute From A to D @ 10 litres/minute From C to D @ 50 litres/minute From B to C @ 100...
try to make he denominator a power of 10 in these kind of problems.quaktar0004 wrote:Thank you for the quick response. Just curious...how did you determine that 8 was the right # to multiply both the numerator and denominator by?
In this case 125 can be converted to closest power of 10 by multiplying it with 8.