actually it's easier than that. the slope is given by the equation (y2-y1)/(x2-x1).

in this case
(-1, -7) and (2, 5)

(5-(-7))/(2-(-1)) = 12/3 = 4
or
((-7)-5)/((-1)-2) = -12/-3 = 4

the trick is that you can't have 3/4 children or men on the trip, it must be an integer. 1) tells you that the number of children must be a multiple of 5, actually, must be a multiple of 10, because multiples of 5 ending in 5 are not multiples of 2 (2 children for each 5 women) so, 10, 20, 30, all a...

answer should be D.

the sets are small enough, just write down the possibilities.
let the employees be a,b and c
office 1 - office 2
--------------------
abc -
ab - c
ac - b
cb - a
a - bc
b - ac
c - ba
- abc

answer is C. from the question let m be Mary's annual salary, j Jim's and k Kate's. m-j=2(m-k) m>j and m>k from 1) j=30k, can't figure out m or k, insufficient from 2)k=40k, can't figure out m or j, insufficient together we know that m>k>j m-30=2(m-40) m-30=2m-80 m=50 so the mean is 50+40+30/3 = 120...

we all agree that the equation simplifies to z =x*z if x=1 z=z and z can be any value, not necessairly 0 if x=0 z must be 0, or else the equation is false. try out in the original equation if x=1 XY+Z= X(Y+Z) results in y+z=y+z 0 = 0, regardless of the value of Z so E can't be right, even if z were ...

I'm actually using it, just not calling it permutations.... "odd numbers end in 1,3,5,7,9. so 5 possibilities" this is 5P1 = 5!/4! = 5 "8 possibilites left for the 2nd digit (can't be 8 or the units digit)" this is 8P1 = 8!/7! = 8 "(for 9) the same applies, but the units dig...

the calculation 4/8*3/7*2/6 is the probability that the 1st, 2nd and 3rd choices are sports magazines. = 24/336 = 1/14

now you want all other options except this one. so 1-1/14 is the answer or 13/14