Yeah, I got D. Statement 1 rules out the only even prime number (2) and guarantees that x will be an odd number. Odd - Odd = Even. Y can be any prime ( 2 or 3,5,7 (odd)) and the product will be even. Statement 2 states Y is 2. Any multiple of 2 is even. D is the answer.

Hi, just found this post while searching for inequality problems. for n^2-m^2 to have maximum value, we need two things. The maximum value of n and the minimum value of m. From the given inequalities, the maximum value of n is 5, and the maximum value of m is 2 (we also know that m <= n, so the mini...

Nevermind. Didn't see Brian's post before. But the restriction of x+y!=0 is brilliant!

E all the way. Statement 1. Factor everything out, you will end up with 2(x-y)=2(x-y). Insufficient. Statement 2. 3x+2y=24. Since 3 (from x) and 2 (from y) are both factors/divisors of 24, you need another equation to solve for x and y. Insufficient. Statement 1 and 2 leaves us with no concrete conc...

This sentence contains two past events. You need a past perfect modifier to distinguish which event occurred first. So B is the right answer. BTW, I'm listening to Little Wing.

If you are confused, first try POE strategy. A and B are wrong; "the result" is a singular noun. E is a fragmented/run-off sentence. Now, you are down to C and D. abhishek.pati's analysis of D is correct. D is too wordy and and awkward. C, on the other hand, is very clear. Choose C.

1) x and y are either 1 or 0 (only two integers that satisfy the equation) 2) x or y is 0 1 and 2) x and y are 0 Is my reasoning correct? Except that y can be 1,-1 nice one phanideepak, forgot about the -1. Yes I didn't bother to expand it. Just seeing the two prompts, I knew than the only possibil...

A quicker way to solve this problem?

This one is from Kaplan CAT (I find it increasingly that most math questions from Kaplan take more than 2 minutes to solve!)

if x + y^2 = ( x + y^2)^2 , what is the value of y?

1. x=y^2
2. xy^2=0 (only y is squared, not xy)

OA c