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Hi there, here comes my first reply ! (let me know if I need to post answers differently) 1) Angle BDC = 60 as it is the complement of ADB (120+60=180) 2) BDC=60 then DBC + DCB = 120, but as BD=DC then DBC=DCB=60 (so an equilateral triangle) 3) Now check that AC =2 but DC=1 therefore AD=1 (AC-DC=2-1...
- by fmillar
Tue Aug 29, 2017 12:21 am- Forum: Problem Solving
- Topic: OG2018 PS In the figure shown
- Replies: 4
- Views: 3082
Hmm... I do not see your point using 9!
because you have 6 players and 3 positions for the guards 6c3 = 20 and 3c2 for the forwards = 3
then to distribute 20 and 3 there are 60 alternatives and that should be the answer.
- by fmillar
Wed Aug 11, 2010 10:51 am- Forum: Problem Solving
- Topic: Basketball Team combos
- Replies: 2
- Views: 914
The answer is E. The 1st statement gives us multiple alternatives: - it could be 7x100 + 700 = 1400 + 1x800 + 100 = 2300. The maximum is 800. - ....but also 7x200 + 700 = 2100 + 1X100 + 100 = 2300. The maximum is 200. Therefore 1 is not enough The 2nd statement does not add more information, and the...
- by fmillar
Tue Aug 10, 2010 8:33 am- Forum: Data Sufficiency
- Topic: defective ATM machine
- Replies: 4
- Views: 1780