You know the definition of the length of an arc and we know the radius of this circle = 9. Thus circumference = 2*pi*9 = 18pi Say T is the centre of the circle ORP = 30 degrees so RPQ = 30 degrees but PTR = 30 degrees (isoceles triangle PTR), thus the two angles TPQ and TQP both equal 70 degrees and...

The median can only be an integer or halfway between integers. Because there are 6 numbers and the first 5 is already divisible by 6, the other number must be a multiple of 3.

THIS DOES NOT SOLVE IT THOUGH

It just help you eliminate 1 quickly

B?

1) Compares only minimum values so x and y can be anything - NOT SUFF

2) Compares the max of x with the minimum of y and because the minimum of y is greater than the maximum of x, y > x SUFF

Application form question

HI Stacey (and anyone who wants to comment), I'm applying to a South African MBA (at UCT) and would like some assistance in completing my application form. The application form has gone through all the essays (which I've written), my CV (which states my accomplishments, experience and skills) and th...

I can't agree more with Stacey. Use Ursula's grid (somewhere on this site) and try and ID a trend in your careless errors.

When checking your answers and you're wrong, before looking at the explanation, do the question again - if you have it wrong again, it might be a concept error.

for a#c to be equal to zero and a <> -c, the numerator of the equation needs to be equal to zero.

i.e. because a#c = (a-c)/(a+c) and a+c is not equal to (<>) 0

The the following ust be true

a - c = 0
ie. a = c

root r/s = s

square botn sides

r/s = s^2

multiply both sides by s

r = s^3

The question should probably have stated: An integer n is prime if....Is n prime?

1) Then SUFF as n =2 or n = 3

2) SUFF (n^2) - 5n + 6 = 0
(n - 3)(n - 2) = 0

n =2 or n = 3