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N is divisible by 65

When N= 2535 ( which is equal to 65 * 39 ) .

In this case N is divisible by both 65 and 39 .


When N = 65 , N is divisible by 65 and not 39 .
Hence 1 is not sufficient ..

by msbinu

Mon Nov 22, 2010 6:23 am
Forum: Data Sufficiency
Topic: Is n Divisible by 39?
Replies: 2
Views: 1326

isn't the answer 2??

0! = 1 (which is a perfect square )
1! = 1 which is also a perfect square

so total 2


Regards,
Binu

by msbinu

Thu Oct 21, 2010 6:05 am
Forum: Problem Solving
Topic: My Wrong Ones...
Replies: 21
Views: 4403

Let the CP for 1 is 1 .

CP for 20 = 20

Let SP for 1 is y

From the given info 20 * 1 = 25 * y
hence y = 20/25 = .8

CP of 1 is 1 and SP for 1 is .8

Hence loss is 20 %

by msbinu

Tue Oct 19, 2010 8:16 am
Forum: Problem Solving
Topic: cost price of 20 articles .........
Replies: 6
Views: 8421

But why dont we have to use permutation also in this sum? Since the sum hints at arrangement ..please help,im confused. Hi , We can use permutation also to solve this. 1 letter code can be selected from 26 letters using 26P1 ways = 26!/25! = 26 2 letter code could be selected in 26P1 * 26 P 1 ways ...

by msbinu

Mon Sep 27, 2010 8:19 am
Forum: Problem Solving
Topic: Combination
Replies: 4
Views: 1573

A square is drawn by joining the midpoints of the sides of a given square. A third square is drawn inside the second square in the same way and this process continues indefinitely. If the side of the first square is 4 cm .determine the sum of the areas of the squares. A. 32 sq.units B. 48 sq.units ...

by msbinu

Wed Sep 22, 2010 8:42 am
Forum: Problem Solving
Topic: Find the sum of the areas of the squares ...................
Replies: 5
Views: 1815

pzazz12 wrote:A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?

(A)10
(B)33
(C)7
(D)8
(E)11
Is it A?

A=B+2
B=2C
A+B+C=27
B+2 + B + B/2 = 27
Solving for B , you will get B =10

by msbinu

Wed Sep 22, 2010 5:34 am
Forum: Problem Solving
Topic: An intresting question from ps..............
Replies: 5
Views: 1282

A square is drawn by joining the midpoints of the sides of a given square. A third square is drawn inside the second square in the same way and this process continues indefinitely. If the side of the first square is 4 cm .determine the sum of the areas of the squares. A. 32 sq.units B. 48 sq.units ...

by msbinu

Wed Sep 22, 2010 5:31 am
Forum: Problem Solving
Topic: Find the sum of the areas of the squares ...................
Replies: 5
Views: 1815

The formula for clock is that

Angle = (60H-11M)/2
=60*2-11*40/2
=160

by msbinu

Wed Sep 22, 2010 5:26 am
Forum: Problem Solving
Topic: Interesting GMATFix Problem-15
Replies: 7
Views: 1319

The question states "units digit of...k is nonzero", therefore it should be A
Ohh .. I missed that .... My mistake :)

by msbinu

Wed Sep 22, 2010 5:23 am
Forum: Data Sufficiency
Topic: Integer and Statistic
Replies: 6
Views: 1448

Hi Selango Tens digit of k+9 is 3. Whatever the unit digit[1..9],when it added with 9,1 is added with tens digit. So tens digit must be always 2 and when added with 1 makes it 3. I think this is not right . What if the unit digit of K is 0 , Then the statement "Whatever the unit digit[1..9],whe...

by msbinu

Tue Sep 21, 2010 8:00 am
Forum: Data Sufficiency
Topic: Integer and Statistic
Replies: 6
Views: 1448

Rules of triangle are 1. length of any side cannot be greater that the sum of other 2 2. Length cannot be shorter than difference of other sides Applying rule 2 Length of third cannot be shorter than 2 . Let the length be 3 . its > 2 and <= 22 ( rule 1 ) length 4 : > 2 and < = 22 . . Length 10 > 2 a...

by msbinu

Fri Sep 10, 2010 9:14 am
Forum: Problem Solving
Topic: integer values of 'x'
Replies: 17
Views: 4872

590 in GMAT

I just finished my GMAT ,... Got only 590 ( Q 45 V27 ) . I was consistently getting around 640 - 680 in all practice tests... NOt sure wht to do now ... :( .. Any suggestion ?

by msbinu

Wed Jun 23, 2010 3:28 am
Forum: GMAT Strategy
Topic: 590 in GMAT
Replies: 1
Views: 981