Search found 5 matches
- by florencejennifer
Tue Mar 09, 2010 3:39 am- Forum: Problem Solving
- Topic: Adding Large Exponents
- Replies: 3
- Views: 6440
Answer Explanation:
By tracing a figure we can identify the no. of such possibilities, and we have at least 5 of such lines.
Correct Answer: D
- by florencejennifer
Tue Mar 09, 2010 3:37 am- Forum: Problem Solving
- Topic: Very Simple Please See and Help!
- Replies: 7
- Views: 1387
There is an error in the construction of the question, if the rotation is made at the center of the square c = c’ and the difference is zero. If the rotation is made at any vertex then it makes some change. This is not a question to work through conventional methods it chould be done by approximat...
- by florencejennifer
Tue Mar 09, 2010 3:34 am- Forum: Problem Solving
- Topic: Square and Distance
- Replies: 11
- Views: 3446
Six sides can be painted six colors in 6! Ways. But each number in the reorientation can take any of the six sides, so we have repetitions in the way of appearance.
i.e., the total number of such arrangements are 6!/6 = 120.
(This is almost similar to circular permutation.)
Correct Answer: E
- by florencejennifer
Tue Mar 09, 2010 3:31 am- Forum: Problem Solving
- Topic: six-sided cube and six cans of paint
- Replies: 27
- Views: 22759
Given W= (5^a*2^b*7^c*3^d) ÷ (5^p*2^q*7^r*3^s)= 2^4 The Primes 5,7, and 3 can be ruled out if their power were equal. Which implies a=p, c=r and d=s i.e 2^b÷2^q = 2^4 2^(b-q) = 2^4 b-q = 4 Since b and q are Hundred digits values b-q=400 Hence K-L= a b c d - p q r s = a b c d- a q c d = 400 z= (K-L...
- by florencejennifer
Thu Feb 25, 2010 10:33 pm- Forum: Problem Solving
- Topic: Z is defined as (K – L) ÷ 10
- Replies: 4
- Views: 2290