Here's how I do it. 120 to 180 included is 61 integers (180-120+1; +1 because of the "included" part), half of which are even. Since 120 and 180 are already even in this set (the extremes), we know we have 31 even integers out of 61. Then you find the average of 120 and 180, which is 150. ...

I think the answer is B). Statement 1 tells us that the score is between 50 and 90. Taking two extremes, 50 and 59, we see that the bonus on 50 would be 10, which is 20% of 50, so the bonus would be greater than 17% of the base score. 59 would still yield a bonus of 10 on the base score, but 0.17*59...

I think the Official Guides and their supplements are the most important, because they contain tons of problems from actual GMAT material. Personally I use the MGMAT quant books to study. They're very well written and go in depth about every subject you're going to find on the test, including specif...

good question!! correct me if i am wrong please! the only way of making a square would be if the dimensions are perfect squares? so in that case if the longer end is 4 mts it would suffice ? how do you get 2/5? on another note, dimensions could be anyting right? cz root2 * root2 could also be the d...

Another approach: A -C + B =even D + B - A = odd Thus, A -C + B + (D + B - A) = odd OR 2B - C + D is odd, since 2B is even, -C + D has to be odd Another option, A -C + B - (D + B - A) = odd OR 2A - (C+D) is odd since 2A is even, C+D has to be odd Hence pick C Brilliant, love it!

I'd say B after an insane approximation, but....drawing it, I got: Basically, the hypothenuse goes from (0,1.4) to (5,0). Using it as the base, since it's a diagonal respectively to the x axis, it's a little more than 5 units long. The height would be from point (2, sqr of 10) to a 90 degree angle o...

the concept which needs to sink in is perhaps... if A+B is even A-B and B-A are also even similarly if A+B is odd A-B and B-A are also odd Exactly. The other thing I really want to take away from this is what to look for in this kind of problem. I had all the necessary knowledge required to find th...

let A=2,B=0,C=0,D=3 Satisfies both A-C+B is even and D + B - A is odd eliminates options D and E let A=1,B=1,c=0,D=3 eliminates A,B pick C Great solution, that's really smart. This problem is really interesting. Is there a way to solve this conceptually without plugging numbers? I know it's probabl...