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jewbagel wrote:ok heres for number 1

(10^8-10^2)=10^2*(10^6-1)
(10^7-10^3)=10^3*(10^4-1)

if you approx 10^6-1 as about 10^6 and 10^4-1 as about 10^4

the equation becomes (10^6)/(10^5)

6-5=1 so its 10^1 or 10


Could you please explain this:
the equation becomes (10^6)/(10^5)

by AlexBee

Tue Dec 01, 2009 7:14 am
Forum: Problem Solving
Topic: Some difficult ones .
Replies: 10
Views: 2333