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lets consider the number to be 'n'. since it has only one more divisor other than 1 and n, n must be a perfect sqare. so say n=x^2(x is a prime).
=> n^2 = x^4
Now divisors of x^4 are 1, x, x^2, x^3, x^4.
i.e 5 divisors.

by sosaha

Sat Apr 21, 2007 10:33 pm
Forum: GMAT Math
Topic: OG 11 math problem solving question
Replies: 3
Views: 6337