The median simply refers to the middle term in an ORDERED list of numbers. For example, if you were given this list... 3, 8, 2, 1, 6 ...first you'd order the numbers, then pick the middle value... 1,2,3,6,8 The median would be 3, because 3 is located at the center of the list. Or, if the number of t...

Take a look at this diagram: http://etc.usf.edu/clipart/49900/49948/49948_construction_md.gif Because it's an equilateral triangle, the lengths of arcs AB, BC, and AC are all equal. That means each is 1/3 of the total circumference of the circle. arc ABC is formed by joining arcs AB and BC, which ea...

Hey Thouraya, I'm wondering if you're actually thinking of the relationship between central angles and inscribed angles. If you take two points on the circumference of a circle and create a central angle (i.e. with the center as the third vertex), the resulting angle will always be twice as large as...

Hey sal_xcool, First of all, the average time per question is more like 2 minutes, so no need to cut yourself off at 1:30! Also, keep in mind that 2 minutes is an AVERAGE. There are going to be some easier problems that you might solve in less than a minute, and some more difficult ones that take yo...

If point X is inside a circle with center O and radius 2, is point Y inside the same circle? (1) OX = 1. Nothing about Y. INSUFFICIENT (2) XY = 2.5. Diameter of the circle is 4, so XY could be entirely within the circle, in which case Y would be inside the circle. However, XY could be a line segment...

Does the product jkmn equal 1?

(1) jk/mn = 1.

jk and mn could both be 1, in which case jkmn would be 1. But jk and mn could both be 2, in which case jkmn would be 4.

INSUFFICIENT

(2) j = 1/k and m = 1/n.

If j=1/k, then jk=1

If m=1/n, then mn=1.

Therefore, jkmn=1.

SUFFICIENT

n(n+1)(n+2) will be divisible by 8 in two situations: 1. n is even. This is because n and n+2 would be consecutive even integers. Even integers always alternate between being multiples of 4 and NOT multiples of 4. So no matter what even integer you chose for n, there will always be a multiple of 4 b...

Unfortunately, no, because you've only tested one set of numbers. You managed to find a case for which the remainder will be 4. But that doesn't mean that there aren't cases for which the remainder will NOT be 4. As an analogy, if I ask if you whether or not a/b is odd, and you plug in a=6 and b=2, ...