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21 litres
Let x be the total vol. B is 5x/12 if we take out 9 litres. then amount of B taken out is 5*9/12=15/4 and we are adding 9 litres of B. but the final volumes remains the same i.e x. And in final volume B is 9*x/16. so the equation will be 5x/12 - 15/4 + 9 = 9*x/16 this gives x= 36. And initial amount...
- by aa2kash
Mon Sep 21, 2009 6:45 am- Forum: Problem Solving
- Topic: Mixture Question
- Replies: 2
- Views: 1004
AS per my understanding; the worm ate 4 books completly and the front cover of the last book + back cover of the first book. each book is 1.5 inch thick. 4 books = 6 inch front cover= .25 inch last cover for the first book= .25 inch I am getting a total of 6.5 inches. which is none of the options. e...
- by aa2kash
Mon Sep 21, 2009 4:58 am- Forum: Problem Solving
- Topic: Help with math problem!
- Replies: 6
- Views: 1634
@Viju
Its mention in the question that they start simultaneously. It means they when they are meeting they have taken the same time to travel their respective distances.So, we can equate the time taken by both of them.
Hope it clears your query now.
- by aa2kash
Sun Sep 20, 2009 1:22 pm- Forum: Problem Solving
- Topic: Speed, Time prob #1
- Replies: 7
- Views: 2352
30 min
Let x be the normal speed. and t is the normal time
then equation 1 can be
xt=15
if he is 1.5times slower than normal speed.then new speed is 2x/3. and as he takes 15 min extra 1.e 1/4 hrs
equation 2 will be
2x/3=15/(t+1/4)
solving these 2 u get
x=30 and t=1/2 i.e 30 mins
- by aa2kash
Sun Sep 20, 2009 7:42 am- Forum: Problem Solving
- Topic: SDT
- Replies: 1
- Views: 1245
- by aa2kash
Sat Sep 19, 2009 9:24 am- Forum: Problem Solving
- Topic: Power Prep Exponent Questions
- Replies: 10
- Views: 1785
Answer is B
draw a line from the centre of the circle to the point D. this is equal to the radius of the circle.
Now u have a right angle traingle with the sides
6, r and r-2
solve it and get r=10.
area of semicircle is pi*r*r/2 = 50pi
- by aa2kash
Sat Sep 19, 2009 9:03 am- Forum: Problem Solving
- Topic: Tough Geom2
- Replies: 4
- Views: 2227
ok. I misread the last line.we have to tell the number of stamps after kay gave 10 stemps to alberto.
as we have solved x=30.
Kay has 5x-10= 140 stamps
Alberto has 3x+10= 100 stamps
difference is 40 stamps.
Answer is c
- by aa2kash
Sat Sep 19, 2009 8:54 am- Forum: Problem Solving
- Topic: GMAT Prep Questions
- Replies: 4
- Views: 1743
thanks Ali for the different and timesaving approach.
I did it with the basic formula, time=dis/speed
since they are meeting after sometime say T. thefore i compared the timetaken by both peter and paul.
70+x is covered by peter and 70-x is covered by paul.
(70+x)/52=(70-x)/39
this gives x=10.
- by aa2kash
Sat Sep 19, 2009 3:48 am- Forum: Problem Solving
- Topic: Speed, Time prob #1
- Replies: 7
- Views: 2352
number one: As the stamps are in the ratio 5:3 say kaye has 5x and alberto has 3x. then after kaye gave 10 stemps to alberto. kaye= 5x-10 alberto=3x+10 and the new ratio is 7:5 solve this: 5x-10/3x+10=7/5 u will get x=30. the difference in the stemps is 5(30)-3(30)=60 the Answer is D 60. number two ...
- by aa2kash
Sat Sep 19, 2009 1:35 am- Forum: Problem Solving
- Topic: GMAT Prep Questions
- Replies: 4
- Views: 1743
Hi Viju
For better understanding of this try to analyse it by putting different values of n. for eg n=5
n!+1 --> 5! +1 =121 which is not divisible by 2,3,4,5 i.e. any number less than or equal to 5 . it is divisible by 11 .
Its a general rule therefore just remember this.
- by aa2kash
Fri Sep 18, 2009 2:30 pm- Forum: Problem Solving
- Topic: Products of consecutive intervals
- Replies: 4
- Views: 1170
There is a simple rule that states that n!+1 cannot be divisible by any number less than or equal to n. modulo arithmetic: n! mod x (where x <= n) = 0 n! + 1 mod x = 1, therefore not divisible by x. In this particular question the function can be written as: h(100) + 1 = (2^50)*50! + 1 therefore it'...
- by aa2kash
Fri Sep 18, 2009 3:51 am- Forum: Problem Solving
- Topic: Products of consecutive intervals
- Replies: 4
- Views: 1170
- by aa2kash
Fri Sep 18, 2009 2:43 am- Forum: Problem Solving
- Topic: PS - Question 55.3.12
- Replies: 2
- Views: 1049