Search found 126 matches
True guys,
now that i read again, its the prod of 1..n multiple of 990 ...
And it ask for the least possible value of n ...
I already had the answer, and I didn't see it.
Thank u both
Silvia
- by ssuarezo
Wed Jun 16, 2010 7:16 pm- Forum: Problem Solving
- Topic: If n is a positive integer
- Replies: 5
- Views: 1271
Using this arc ABC = 2/3 perimeter of triangle = 2(pi)r * 2/3 This should be: 24 = (2/3)*circumference of circle = (2/3)*2*pi*r and we want 2r, so: 2r = 36/pi = approx. 11 Thank u guys, I understood what Asamaverick wanted to say, but as testLuv noted, it s always good to use the exact terminology....
- by ssuarezo
Wed Jun 16, 2010 7:10 pm- Forum: Problem Solving
- Topic: Triangle inscribed in circle
- Replies: 4
- Views: 1347
I didnt understand what per capita meant. It just means per person. Notice that the population increased by a greater percentage than did cigarette consumption (5 vs 3.4). Thus, per-person (or per capita) cigarette consumption in '76 must be lower than it was in '73. Thank you guys, Explained the w...
- by ssuarezo
Wed Jun 16, 2010 7:00 pm- Forum: Problem Solving
- Topic: From 1973 to 1976
- Replies: 3
- Views: 2124
If n is a positive integer and the product of all the itnegers from 1 to n, inclusive is a multiple of 990, what is the least possible value of n? 10 11 12 13 14 990 =9*10*11 so it should contain 9 ,10 and 11 so smallest possible value of n could be 11 (as you can see if you take product from 1 to ...
- by ssuarezo
Wed Jun 16, 2010 6:49 pm- Forum: Problem Solving
- Topic: If n is a positive integer
- Replies: 5
- Views: 1271
soln: dealer purchase price =150 selling price put by dealer sp= 150+ 40%of sp sp= 150+(40/100)*sp sp= 150+0.4 sp 0.6 sp= 150 sp= (150/0.6)=250 so dealer gross profit = Selling price - purchase price = 250 - 150 =100 Thanks again Amising6 It seems so logic when I see it: if I take 40% of SP as a ma...
- by ssuarezo
Wed Jun 16, 2010 6:33 pm- Forum: Problem Solving
- Topic: A furniture dealer purchased a desk
- Replies: 4
- Views: 3365
given 90 % attended first day statement 1)1000 people registered for seminar so 900 came for first day but we dont have any information about seconday day statement 2) let poulation be X so second day attendance 0.8x i.e 80% of X we know that first day attendance for seminar ewas 0.90 x i.e 90 % of...
- by ssuarezo
Wed Jun 16, 2010 6:28 pm- Forum: Data Sufficiency
- Topic: At a two-day seminar
- Replies: 4
- Views: 1675
- by ssuarezo
Wed Jun 16, 2010 6:19 pm- Forum: Data Sufficiency
- Topic: Six countries
- Replies: 6
- Views: 1984
- by ssuarezo
Wed Jun 16, 2010 6:16 pm- Forum: Data Sufficiency
- Topic: Jason's salary
- Replies: 4
- Views: 2142
- by ssuarezo
Wed Jun 16, 2010 6:12 pm- Forum: Data Sufficiency
- Topic: At a two-day seminar
- Replies: 4
- Views: 1675
- by ssuarezo
Wed Jun 16, 2010 6:07 pm- Forum: Data Sufficiency
- Topic: On Jane's credit card
- Replies: 3
- Views: 1313
- by ssuarezo
Wed Jun 16, 2010 6:04 pm- Forum: Data Sufficiency
- Topic: In the figure shown
- Replies: 4
- Views: 1785
if we solve for only first few terms t(1)=+1/2 (putting k=1 in kth ter sequence given) t(2)=-1/4 t(3)=1/8 t(4)=-1/16 so you can say all odd will be positive and all even term will be negative if you take only t(1) and t(2)=+1/2 - 1/4=1/4 now going fore ward t(3)and t(4)=+1/8 - 1/16=1/16 t(5) and t(...
- by ssuarezo
Wed Jun 16, 2010 5:56 pm- Forum: Problem Solving
- Topic: For every integer K (Exam on Friday!)
- Replies: 2
- Views: 1104
xy =1 (2^(x+y)^2)/(2^(x-Y)^2) now we will use one concept which say that a^b/a^c=a^(b-c) so we can reduce the given problem to 2 ^(((x+y)^2)-((x-y)^2)) 2^(x^2+y^2+2xy -(x^2+y^2 - 2xy)) as we know (a+b)^2=a^2+b^2+2ab and (a-b)^2=a^2+b^2-2ab 2^(4xy) since remaining term will cancel out 2^(4*1) 2^4=16...
- by ssuarezo
Wed Jun 16, 2010 5:51 pm- Forum: Problem Solving
- Topic: If xy=1
- Replies: 2
- Views: 1091
- by ssuarezo
Wed Jun 16, 2010 5:43 pm- Forum: Problem Solving
- Topic: From 1973 to 1976
- Replies: 3
- Views: 2124
The number of stamps
The number of stamps that Kaye and albert had was inthe ratio of 5:3, After Kaye gave albert 10 of her stamps, the ratio of the number of stamps that Kaye had to the number Albert had was 7:5. As a result of the gift, Kaye had how many more stamps than albert?
20
30
40
60
90
Thnks
Silvia
- by ssuarezo
Wed Jun 16, 2010 5:40 pm- Forum: Problem Solving
- Topic: The number of stamps
- Replies: 9
- Views: 1455