Search found 59 matches
Re: GMATPrep Tough Questions
1) (-1^(k+1)).(½^k). T is the sum of the first 10 k, is t a. > 2 b. between 1 and 2 c. between ½ and 1 d. between ¼ and ½ e. < ¼ Answer: D Explanation: lets substitute k= 1,2,3 and 4 that gives us the value of the expression as 1/2, -1/4, 1/8, -1/16 and so we now know the pattern. Since T is summat...
- by Pranay
Thu Jun 11, 2009 3:58 am- Forum: Problem Solving
- Topic: GMATPrep Tough Questions
- Replies: 18
- Views: 4053
Re: boxes
IMO 5!ketkoag wrote:A store boss can buy two kinds of goods, X: 32/box; Y: 40/box. If he plan to buy same quantity of X and Y, at least how many boxes of X should he buy?`
Please post the OA.
- by Pranay
Thu Jun 11, 2009 3:55 am- Forum: Problem Solving
- Topic: boxes
- Replies: 6
- Views: 1617
Re: GMATPrep Tough Questions
1) (-1^(k+1)).(½^k). T is the sum of the first 10 k, is t a. > 2 b. between 1 and 2 c. between ½ and 1 d. between ¼ and ½ e. < ¼ Ans. C 2) If x ≠ 0, then √(x^2)/x = a. -1 b. 0 c. 1 d. x e. |x|/x Ans. E 3) If n is a positive integer less than 200 and 14n⁄60 is also an in...
- by Pranay
Thu Jun 11, 2009 3:26 am- Forum: Problem Solving
- Topic: GMATPrep Tough Questions
- Replies: 18
- Views: 4053
yep .. IMO C. Clock 1 advances 120 mins per day. Clock 2 lags 72 mins per day. Clock 3 is on time. Implies, Clock 1 needs 12 days to make it to midnight including the delay. Clock 2 needs 20 days to make it to midnight including the delay. By running through the options I got 30 days. Can someone gi...
- by Pranay
Tue Jun 09, 2009 1:32 am- Forum: Problem Solving
- Topic: gertrude's grandma with grandfather's clocks
- Replies: 4
- Views: 2009
- by Pranay
Mon Jun 08, 2009 3:34 am- Forum: Problem Solving
- Topic: Please help in this question
- Replies: 4
- Views: 2473
Re: Radius of Circle
Hi .. The answer is D. Using the Trignometry concepts, I could get that angle ADP is 45 degrees. (Applying tan inverse to each of the right angled triangles ADP and BDP) Using a theorm, the angles subtended by a chord at the edge of a circle is half that of subtended at the centre implies, angle AOB...
- by Pranay
Mon Jun 08, 2009 3:17 am- Forum: Problem Solving
- Topic: Radius of Circle
- Replies: 5
- Views: 1580
Re: Radius of Circle
Let AB and CD be two chords of a circle that intersect at a point P. Suppose that AP = 4, PB = 6, CP = 2, PD = 12 and Angle APC = 90◦. What is the radius of the circle? (a) 4√3 (b) 3√6 (c) 8 (d) 5√2 (e) √47 I reached 2 root(5). Please confirm the op...
- by Pranay
Thu Jun 04, 2009 4:33 am- Forum: Problem Solving
- Topic: Radius of Circle
- Replies: 5
- Views: 1580
Re: Radius of Circle
Let AB and CD be two chords of a circle that intersect at a point P. Suppose that AP = 4, PB = 6, CP = 2, PD = 12 and Angle APC = 90◦. What is the radius of the circle? (a) 4√3 (b) 3√6 (c) 8 (d) 5√2 (e) √47 I reached 2 root(5). Please confirm the op...
- by Pranay
Thu Jun 04, 2009 3:25 am- Forum: Problem Solving
- Topic: Radius of Circle
- Replies: 5
- Views: 1580
Re: GMAT prep: one of the four arithmetic operations
I go with C i.e., both answer taken together.
Option 1 says the sign can be either + or *.
Option 2 says the sign can be either + or -.
Thus using both, we can conclude the sign is +.
- by Pranay
Thu Jun 04, 2009 3:10 am- Forum: Problem Solving
- Topic: GMAT prep: one of the four arithmetic operations
- Replies: 8
- Views: 4952
Re: Gmat prep ! Ques
Hi Guys,
My Procedure is,
Divide the number 75 into three numbers such that each number has a square and when all the three are added they sum up to 75.
I split it this way
50+25=75
49+1+25 = 75
7^2 + 1^2 + 5^2 = 75.
Thus, 7+1+5 = 13 is the answer.
Hope it helps. 
- by Pranay
Tue Jun 02, 2009 4:14 am- Forum: Problem Solving
- Topic: Gmat prep ! Ques
- Replies: 3
- Views: 1193
- by Pranay
Tue May 19, 2009 9:26 pm- Forum: Problem Solving
- Topic: stock
- Replies: 7
- Views: 1418
Re: stock
I am getting 560% increase ... !!!!!!! 
May be because options are not available .. !
Anyways whats the answer .. ??
Please correct if wrong.
Regards,
Pranay
- by Pranay
Tue May 19, 2009 4:47 am- Forum: Problem Solving
- Topic: stock
- Replies: 7
- Views: 1418
Re: General concept
What is the remainder when 7^625 is divided by 15? [spoiler]Now, i got that by power cycle the unit's digit will be 7, but how the answer to the question above is 7?[/spoiler] Hi, When 7^8 is divided by 15 the remainder left is 1. Thus, 7^625 = [(7^8)^78].7 Since, when 7^8 divided by 15 leaves a re...
- by Pranay
Tue May 19, 2009 4:33 am- Forum: Problem Solving
- Topic: General concept
- Replies: 3
- Views: 1193
Re: O.G 12 PS 89
Hi Syr,
Great solution.
Hi ssmiles08,
Its been long time since I am looking for an OG12.
Could you please let me know the source for it. It would be great if you can share incase you have a soft copy of it.
My E-Mail is - [email protected]
It would be really helpful.
Pranay.
- by Pranay
Thu May 14, 2009 2:17 am- Forum: Problem Solving
- Topic: O.G 12 PS 89
- Replies: 3
- Views: 1294
Re: Number of defects
The number of defects in the first five cars to come through a new production line are 9, 7, 10, 4, and 6, respectively. If the sixth car through the production line has either 3, 7, or 12 defects, for which of theses values does the mean number of defects per car for the first six cars equal the m...
- by Pranay
Wed May 13, 2009 10:07 pm- Forum: Problem Solving
- Topic: Number of defects
- Replies: 2
- Views: 2718